Ask question

Ask question

All categories

2 years ago

12

Help!! Number 39 please

2 answers:

antiseptic1488 [7]2 years ago

8 0

Keep in mind you would need a total of 120 ounces.
A: Corn cereal comes in 12 oz boxes and the person used 5 boxes, thus taking 60 oz away from the total, leaving 60 oz. Next, you’d have to divide 60 oz by 4 (since that’s how many boxes of wheat cereal were used). Resulting in a wheat box being worth 15 ounces!!
B: 12c+ 15w= 120 (c= corn cereal, w= wheat cereal)
C: 5 boxes of corn cereal with 4 boxes of wheat cereal; 0 boxes of corn cereal with 8 boxes of wheat cereal; 10 boxes of corn cereal with 0 boxes of wheat cereal.

kenny6666 [7]2 years ago

3 0

Answer:

a. is 15 ounces each box

b. 120=12c+15w

c. 5 box of corn and 4 boxes of wheat i was a little confused on this one because does it have to include both cereals in the mix or just one

Step-by-step explanation:

to find a its

if 12 times 5 equals 60 then theres 60 ounces left if you use 4 boxes you divide 60 by 4 and get 15

You might be interested in

Use the distributive property to remove the parentheses.<br> -3(-6y +3w-2)

LekaFEV [45]

Answer:

18y-9w+6

Step-by-step explanation:

-3*-6y=18y

-3*3w=-9w

-3-2=6

so, 18y-9w+6

3 0

2 years ago

Read 2 more answers

Put 5x + 5y = -3,500 into a slope-intercept form

GREYUIT [131]

Slope intercept form is y=mx+b
y=-x+700

4 0

2 years ago

Read 2 more answers

Estimate 200 times 3

Sonja [21]

I "estimate" 600....?

7 0

3 years ago

Read 2 more answers

The core melt- down and explosions at the nuclear reactor in Chernobyl in 1986 released large amounts of strontium-90, which dec

elena-14-01-66 [18.8K]

If $S(t)$ is the amount of strontium-90 present in the area in year $t$ , and it decays at a rate of 2.5% per year, then

$S(t+1)=(1-0.025)S(t)=0.975S(t)$

Let $S(0)=s$ be the starting amount immediately after the nuclear reactor explodes. Then

$S(t+1)=0.975S(t)=0.975^2S(t-1)=0.975^3S(t-2)=\cdots=0.975^{t+1}S(0)$

or simply

$S(t)=0.975^ts$

So that after 50 years, the amount of strontium-90 that remains is approximately

$S(50)=0.975^{50}s\approx0.282s$

or about 28% of the original amount.

We can confirm this another way; recall the exponential decay formula,

$S(t)=se^{kt}$

where $t$ is measured in years. We're told that 2.5% of the starting amount $s$ decays after 1 year, so that

$0.975s=se^k\implies k=\ln0.975$

Then after 50 years, we have

$S(50)=se^{50k}\approx0.282s$

5 0

2 years ago

What is the value of m in the ecuation 1/2m -3/4n = 16, when n =8 ?

soldi70 [24.7K]

Answer: m=44

Step-by-step explanation:

1/2m-3/4n = 16

1/2m-3/4(8) = 16

1/2m-24/4 = 16

1/2m-6 = 16

1/2m = 22

m=44

8 0

1 year ago