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2 years ago

On a graph with y-values ranging from 1,010,020 to 9,682,192, what is a reasonable scale to use on a y-axis with 10 tick marks?

1 answer:

7 0

Divide the range by the number of marks: [9682192 - 1010020] / 10 = 867.217

So a reasonable scales is millions and the marks will be, 1 million, 2 million, 3 million, 4 million, ... until 10 million

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If the length of a rectangular field is twice the width and the perimeter is 24. Write an equation that an be used to solve for

Sedbober [7]

If we use the width as x we have 2x with both widths and 4x with both lengths. So 6x=24 and x=4. So length is 8 and width is 4.

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3 years ago

Question 3- Please help. Find the area of the sector for the image below:

bezimeni [28]

Answer:

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2 years ago

Which is a graph for the inequality m < -2 ?

aliya0001 [1]

Answer:

Step-by-step explanation:

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3 years ago

An equation of the line that passes through the point (0, -1)<br> and whose slope is 2 is

BARSIC [14]

I believe that it is y=2x-1

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2 years ago

Read 2 more answers

Helpppppppppppppppppppp

Sloan [31]

Answer:

Sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$ is $\mathbf{\frac{9x-4}{x^2-4}}$

Option B is correct answer.

Step-by-step explanation:

We need to find sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$

Finding sum of $\frac{7}{x^2-4}$ and $\frac{2}{x+2}$ :

$\frac{7x}{x^2-4}+\frac{2}{x+2}$

We know that $x^2-4 =(x+2)(x-2)$

Replacing x^2-4

$\frac{7x}{(x+2)(x-2)}+\frac{2}{x+2}$

Now, taking LCM of (x+2)(x-2) and (x+2) we get (x+2)(x-2)

$=\frac{7x+2(x-2)}{(x+2)(x-2)}\\=\frac{7x+2x-4}{(x+2)(x-2)}\\=\frac{9x-4}{(x+2)(x-2)}\\=\frac{9x-4}{x^2-4}$

So, Sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$ is $\mathbf{\frac{9x-4}{x^2-4}}$

Option B is correct answer.

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2 years ago