Answer:
Here we will use the relationships:



And a number:

is between 0 and 1 if a is positive and larger than 1, and n is negative.
if a is positive and 0 < a < 1, then we need to have n positive such that:
0 < a^n < 1
A) 
This is between zero and 1,
B) 
This is greater than 1, because the exponent is positive.
C) 
Because a is smaller than 1, and the exponent is positive, then the expression is between 0 and 1.
D) 
The exponent is negative (and pair) then the expression is between 0 and 1.
Remember that when the exponent is pair, we always have that:
(-N)^m = (N)^m
So (-7)^-2 = 7^-2
<h3>
Answer: 864</h3>
=======================================================
Work Shown:
There are,
- 3 sizes of coffee
- 4 types of coffee
- 2 choices for cream (you pick it or you leave it out)
- 2 choices for sugar (same idea as the cream)
This means there are 3*4*2*2 = 12*4 = 48 different coffees. We'll use this value later, so let A = 48.
There are 6 bagel options. Also, there are 3 choices in terms of if you order the bagel plain, with butter, or with cream cheese. This leads to 6*3 = 18 different ways to order a bagel. Let B = 18.
Multiply the values of A and B to get the final answer
A*B = 48*18 = 864
There are 864 ways to order a coffee and bagel at this restaurant.
--------------
If you're curious why you multiply the values out, consider this smaller example.
Let's say you had 3 choices of coffee and 2 choices for a bagel. Form a table with 3 rows and 2 columns. Place the different coffee choices along the left to form each row. Along the top, we'll have the two different bagel choices (one for each column).
This 3 by 2 table leads to 3*2 = 6 individual table cells inside. Each cell in the table represents a coffee+bagel combo. This idea is applied to the section above, but we have a lot more options.
Answer:
thats way to much
Step-by-step explanation:
OK
Answer:n= 1/3d - 2/3m
Step-by-step explanation:
d=2m+3n
Step 1: Flip the equation.
2m+3n=d
Step 2: Add -2m to both sides.
2m+3n+−2m=d+−2m
3n=d−2m
Step 3: Divide both sides by 3.
3n/3 = d-2m/3
Therefore
n= 1/3d - 2/3m
Hope this helps!
Plz name brainliest if possible.
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Answer:
n = d - 2m
3*
Step-by-step explanation:
First we want to get n alone on one side, so we should subtract 2m from both side;
d = 2m + 3n
3n = d - 2m
Now to get n by itself, we need to divide by 3 from both sides;
3n = d - 2m
n = d - 2m
3*
*Pretend there is a fraction bar between d - 2m and 3
Step-by-step explanation: