Answer:
the maximum concentration of the antibiotic during the first 12 hours is 1.185
at t= 2 hours.
Step-by-step explanation:
We are given the following information:
After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in 

Thus, we are given the time interval [0,12] for t.
- We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
- The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.
First, we differentiate C(t) with respect to t, to get,

Equating the first derivative to zero, we get,

Solving, we get,

At t = 0

At t = 2

At t = 12

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185
at t= 2 hours.
<u>Given</u>:
The given equation is 
We need to determine the approximate value of q.
<u>Value of q:</u>
To determine the value of q, let us solve the equation for q.
Hence, Subtracting
on both sides of the equation, we get;

Subtracting both sides of the equation by 2q, we have;

Dividing both sides of the equation by -1, we have;

Now, substituting the value of
, we have;

Subtracting the values, we get;

Thus, the approximate value of q is 0.585
Hence, Option C is the correct answer.
Equation :
[x(x+4)]/2=6 (as (b*h)/2=A)
x*x + 4*x -12 = 0
so, x = 2 units(as -6 is negative)
Answer:
The First one is the answer
Answer:
They have 6 when multiplying it
Step-by-step explanation: