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3 years ago

Ali bounces a ball while Tim counts. Tim counts 11 tens and 2 ones. How many bounces did Tim count?

Mathematics

1 answer:

elena55 [62]3 years ago

8 0

Tim counts:
11 tens:
11x10=110
and 2 ones:
110+2= 112
Tim counted 112 bounces.

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2x - 2y = -8 x + 2y = -1 (-3,1) O (-14, 1) (0,4) (1,5)

trasher [3.6K]

Answer:

2x - 2y = -8

x + 2y = -1

3x = -9

x = -3

-3 + 2y = -1

2y = 2

y = 1

(-3, 1) is the solution

Step-by-step explanation:

6 0

2 years ago

At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. T

elixir [45]

Answer:

$\text{Exact area of the sidewalk}=40 \pi\text{ m}^2$

$\text{Approximate area of the sidewalk}=125.6\text{ m}^2$

Step-by-step explanation:

We have been given that at a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m.

To find the area of the side walk we will subtract the area of inner edge of the side walk of lion pen from the area of the outer edge of the lion pen.

$\text{Area of circle}=\pi r^2$ , where r represents radius of the circle.

$\text{Exact area of the sidewalk}=\pi*\text{(11 m)}^2-\pi*\text{(9 m)}^2$

$\text{Exact area of the sidewalk}=\pi*\text{121 m}^2-\pi*\text{81 m}^2$

$\text{Exact area of the sidewalk}=40 \pi\text{ m}^2$

Therefore, the exact area of the side walk is $40 \pi\text{ m}^2$

To find the approximate area of side walk let us substitute pi equals 3.14.

$\text{Approximate area of the sidewalk}=40*3.14\text{ m}^2$

$\text{Approximate area of the sidewalk}=125.6\text{ m}^2$

Therefore, the approximate area of the side walk is $125.6\text{ m}^2$ .

5 0

2 years ago

What is the area of a rectangle that is 1 1/4 m long and 3/4 of a meter wide

Marat540 [252]

Answer:

the answer for this question is 15/14

to find area the formula is area = l×b

here length is 1 1/4 and breadth is 3/4 so l×b = 1 1/4=5/4 so 5/4×3/4=15/14

5 0

2 years ago

vani is building a rectangular play area. The length of the play area is 7.5 meters. The width of the play area is 5.3 meters. I

horsena [70]

39.75 square meters

5 0

3 years ago

5000 people went to vote. Candidate Smith claimed 52% of the votes. Candidate Adams claimed 2681 votes. What percentage does can

boyakko [2]

The percentage of votes claimed by Adam is 53.62 %

Solution:

Given that, 5000 people went to vote

Candidate Smith claimed 52% of the votes. Candidate Adams claimed 2681 votes

To find: Percentage claimed by Adam

From given,

Total number of votes = 5000

Votes claimed by Adam = 2681

The formula used is:

$Percentage\ claimed\ by\ Adam = \frac{\text{votes claimed by adam}}{\text{Total number of votes}} \times 100$

Substituting the values we get,

$Percentage\ claimed\ by\ Adam = \frac{2681}{5000} \times 100\\\\Percentage\ claimed\ by\ Adam = 0.5362 \times 100\\\\Percentage\ claimed\ by\ Adam = 53.62$

Thus percentage of votes claimed by Adam is 53.62 %

3 0

2 years ago