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ohaa [14]
3 years ago
11

Find the sum of the first six terms of the sequence. S6 = ⇒ 84

Mathematics
1 answer:
k0ka [10]3 years ago
7 0

Answer:

Explained below.

Step-by-step explanation:

Consider the series is a set of first 6 natural numbers.

Sum of first <em>n</em> terms is:

\text{Sum of n terms}=\frac{n(n+1)}{2}

\text{Sum of first 6 terms}=\frac{6(6+1)}{2}

                               =3\times7\\=21

Consider the series is an arithmetic sequence.

Sum of first <em>n</em> terms is:

S_{n}=\frac{n}{2} [2a+(n-1)d]

Here<em>,</em>

<em>a</em> = first term

<em>d</em> = common difference

Consider the series is an geometric sequence.

Sum of first <em>n</em> terms is:

S_{n}=\frac{a_{1}\cdot(1-r^{n})}{(1-r)}

Here<em>,</em>

<em>a₁</em> = first term

<em>r</em> = common ratio

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