Answer: If i'm correct i think the subsets of b are
={0},{1},{2},{0,1},{1,2} ,{2,0},{0,1,2},{phye}
Step-by-step explanation:
Answer:
y² = x² - z²
Step-by-step explanation:
x² - y² = z²
Transpose y the other side
x² - z² = y²
or
y² = x² - z²
<h3>
Answer: 8/25</h3>
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Explanation:
In a standard deck, there are 52 cards.
If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.
There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.
Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.
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The event space has A = 16 cards in it, while the sample space has B = 50 cards.
The probability we're after is A/B = 16/50 = 8/25
Answer:
DGH has a different number than Ce and FI
2x-6=2x+2
We move all terms to the left:
2x-6-(2x+2)=0
We get rid of parentheses
2x-2x-2-6=0
We add all the numbers together, and all the variables
-8!=0
There is no solution for this equation
