Vertex form is basically commplete the square
y=a(x-h)^2+k
y=x^2+14x+4
take 1/2 of 14 and square it, (7^2=49)
add that and its negative to right side
y=x^2+14x+49-49+4
factor perfect squaer
y=(x+7)^2-49+4
y=(x+7)^2-45
answer is A
Answer: 6 hours
Step-by-step explanation:
You would first start by making 1 3/5 into a mixed fraction. Getting 8/5. Then you’d divide that by 3/4 and get 6/5. Which then you’d multiply it by 5 and get 6 hours.

We know that, in ∆ABC,
∠A+∠B+∠C = 180°
But the triangle is right angled at C
ie., ∠C = 90°
Therefore, ∠A+∠B+ 90° = 180°
⇒ ∠A + ∠B = 90°
Therefore, <u>cos(A + B) = cos 90º = 0</u>
We are given 2 sides 18.7, 16.1 and a NON-included angle.
We have to calculate the altitude of the triangle.
altitude = 18.7 * sine (35)
altitude = 18.7 * 0.57358
altitude =
<span>
<span>
<span>
10.725946
</span>
</span>
</span>
In this case, side c is greater than the altitude and is less than side a so 2 two triangles will be formed.
Source:
http://www.1728.org/trigssa.htm
Answer:
no I don't know I am sorry for this question