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3 years ago

What are the solution(s) of x squared minus 4 = 0? x = negative 4 or x = 4 x = negative 2 or x = 2 x = 2 x = 4

Mathematics

2 answers:

frosja888 [35]3 years ago

7 0

Answer:

Step-by-step explanation:

The expression is

x^2 - 4

This is a quadratic expression.

To find the solution, we will equate the the expression to zero. It becomes

x^2 - 4 = 0

Add 4 to the left hand side of the equation and the right hand side of the equation. It becomes.

x^2 - 4 + 4 = 0 + 4

x^2 = 4

Take square root of the right hand side of the equation and left hand side of the equation. It becomes

√x^2 = √4

x = ± 2

x = 2 or x = - 2

Pani-rosa [81]3 years ago

5 0

Answer:

Step-by-step explanation:

edg 2020

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Naddik [55]

Answer:

Step-by-step explanation:

The volume (V) of the prism is calculated as

V = lbh ( l is length, b breadth and h is height )

Here l = 7, b = 2 and h = 4 , thus

V = 7 × 2 × 4 = 56 in² → D

3 0

3 years ago

Read 2 more answers

Indicate the equation of the given line in standard form.

s2008m [1.1K]

The line through (a,b) with slope m is

y-b = m(x-a)

Here that's

y + 1 = (3/4) (x - 2)

Let's multiply by 4 to clear the fractions and distribute the constants,

4y + 4 = 3x - 6

Rearranging into standard form,

3x - 4y = 10

Check. The slope is 3/4, good. 3(2) - 4(-1) = 6+4 = 10 good

Answer: 3x - 4y = 10

6 0

3 years ago

1. 5/6 x10

REY [17]

Do you need decimal, exact form, or mixed number?

6 0

3 years ago

Read 2 more answers

Use an equation to find the value of k so that the line that passes through the given slope (1,3) , (5,k) m=2

scoray [572]

Answer:

The value of k with given points and slop = 11

Step-by-step explanation:

Given that a line passes through two points having slop (m) = 2

co ordinates of points are (1 , 3) and (5 , k)

Now slop of line can be written as,

Slop = $\frac{(y2 - y1)}{(x2 - x1)}$

Or, m = $\frac{(y2 - y1)}{(x2 - x1)}$

2 = $\frac{(k - 3)}{(5 - 1)}$

Or, 2 = $\frac{(k - 3)}{(4)}$

So , k - 3 = 8

∴ K = 8+3 = 11

Hence the value of k with given points and slop = 11 Answer

5 0

3 years ago

Find the equation of the tangent line to the curve y equals left parenthesis x minus 3 right parenthesis superscript 7 baseline

Rashid [163]

We have been given the expression to be $y=(x-3)^7(x+1)^2$

Since we need to find the tangent at a point, we will have to find the derivative of $y$ as the slope of the tangent at a given point on the curve is always equal to value of the derivative at that point.

Thus, we have to find $\frac{dy}{dx}=\frac{d}{dx} (x-3)^7(x+1)^2$

We will use the product rule of derivatives to find $\frac{dy}{dx}$

Thus, $y'=7(x-3)^6(x+1)^2+(x-3)^7\times2(x+1)$ (using the product rule which states that $(fg)'=f'g+fg'$ )

Taking the common factors out we get:

$y'=(x-3)^6(x+1)(7(x+1)+2(x-3))$

$y'=(x-3)^6(x+1)(7x+7+2x-6)=(x-3)^6(x+1)(9x+1)$

Thus, $y'$ at $x=4$ is given by:

$y'_{x=4}$ =Slope of the tangent of y at x=4= $m$

Thus, $m=(4-3)^6(4+1)(9\times4+1)=185$

Now, the equation of the tangent line which passes through $(x_{1}, y_{1})$ and has slope m is given by:

$y-y_{1}=m(x-x_{1})$

Thus, the equation of the tangent line which passes through $(4,25)$ and has the slope 185 is $y-25=185(x-4)$

Which can be simplified to $y=185x-740+25=185x-715$

Thus, $y=185x-715$

This is the required equation of the tangent.

3 0

3 years ago