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xxTIMURxx [149]
3 years ago
6

7x+3(×+6)=8 .....whut , it makes NO SENSE!!!!!!!

Mathematics
2 answers:
Olegator [25]3 years ago
7 0

Answer:

so first do 3(x+6) so multiply 3*x and 3*6

then you get 7x+3x+18=8

the add all like terms 7x+3x

then you get 10x+18=8

now subtract 18 from both sides to get x by its self 10x+18-18=8-18

then you get 10x=-10

no divide each side by 10x

then you get x=-1

Step-by-step explanation:


CaHeK987 [17]3 years ago
3 0

the answer would be -1 hope this helps

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Y/0.5=16<br><br> Please solve the equation ‍♀️
sweet-ann [11.9K]

Answer:

y=8

Step-by-step explanation:

y/0.5=16

multiply each side by 0.5 and you get y=8

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Step-by-step explanation:

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1. Two segments from P are tangent to circle o. If angle P = 60 and the radius of circle o is
GaryK [48]

Answer:

20.7 ft each

Step-by-step explanation:

See the diagram attached below which describes and represents the information given to us.

The tangents are PA and PB.

Tangents form right angle with the radius of a circle, therefore:

<OBP = <OAP = 90°

Therefore ∆OBP is a right triangle.

m<APO = m<BPO = ½(60) = 30°

Thus, in ∆OBP,

Reference angle = 30°

Side length opposite to reference angle = 12 ft

Adjacent length = length of tangent PB

Apply trigonometric function TOA, to find PB:

Tan 30 = Opp/Adj

Tan 30 = 12/PB

PB × Tan 30 = 12

PB = 12/Tan 30

PB = 20.7846097 ≈ 20.7 ft (nearest tenth)

Length of each segment = 20.7 ft

3 0
3 years ago
The table shows the number of tropical cyclones that formed during the hurricane
kifflom [539]

a = 46.2 b = 46.9

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An old bone contains 80% of its original carbon-14. Use the half-life model to find the age of the bone. Find an equation equiva
Ira Lisetskai [31]

Answer:

An old bone contains 80% of its original carbon-14 in 1844.6479 years

Step-by-step explanation:

We know that

half life time of C-14 is 5730 years

so, h=5730

now, we can use formula

P(t)=P_0(\frac{1}{2})^{\frac{t}{h} }

we can plug back h

and we get

P(t)=P_0(\frac{1}{2})^{\frac{t}{5730} }

An old bone contains 80% of its original carbon-14

so,

P(t)=0.80Po

we can plug it and then we solve for t

0.80P_0=P_0(\frac{1}{2})^{\frac{t}{5730} }

0.80=(\frac{1}{2})^{\frac{t}{5730} }

\ln \left(0.8\right)=\ln \left(\left(\frac{1}{2}\right)^{\frac{t}{5730}}\right)

t=-\frac{5730\ln \left(0.8\right)}{\ln \left(2\right)}

t=1844.6479

So,

An old bone contains 80% of its original carbon-14 in 1844.6479 years


4 0
3 years ago
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