1800
LCM of 10 and 15 = 30
LCM of 6 and 20 = 60
30(60) = 1800
Answer:
yes
Step-by-step explanation:
Answer:
<em>Ed had 5 books and each book had 100 pages and it takes him 50 mins to read each book how many books can he read in a day? </em>
<em>sorry if it's not good I try.</em>
Step-by-step explanation:
Answer:


And the best option would be:
4. Minimum: 869.69; maximum: 961.17
Step-by-step explanation:
We can assume that the variable of interst X is distributed with a binomial distribution and we can use the normal approximation.
For this case the mean would be given by:

And the standard deviation would be:

And if we find the limits we got:


And the best option would be:
4. Minimum: 869.69; maximum: 961.17