I just graphed the table next to the graph of g and compared the two.
The y-intercept of f is (0,8) and the y-intercept of g is (0, -2). So f is GREATER THAN the y-intercept of g.
Now to do the average rate of change, I see from the interval [-6,-3] that f is decreasing and for g it is increasing. Thus f is LESS THAN the average rate of change of g.
Let +n+ = number of bottles of cranberry juice needed
+2n+ = number of bottles of ginger ale needed
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+3.2n+%2B+.9%2A%28+2n+%29+=+20+
+3.2n+%2B+1.8n+=+20+
+32n+%2B+18n+=+200+
+50n+=+200+
+n+=+4+
and
+2n+=+8+
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The most bottles of cranberry juice is 4
B,c,c,a those are the answers :))
<span>A value that "lies outside" (is much smaller or larger than) most of the other values in a set of data</span>
