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2 years ago

Solve 6a + (8b + 2a) = 6a + (2a + 8b)

1 answer:

8 0

★ Linear Reduction ★

6a + ( 8b + 2a ) = 6a + ( 2a + 8b )

6a + 8b + 2a = 6a + 8b + 2a

Hence , a = b = c is the only possible set available in real numbers

(a = b = c) ∈ R

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The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re

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Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic clarithromycin is eliminated from the body according to the formula:

$A(t) = 500e^{-0.1386t}$ ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

$100= 500e^{-0.1386t}$

Divide both sides by 500 we get;

$\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}$

Simplify:

$\frac{1}{5} = e^{-0.1386t}$

Taking logarithm both sides with base e, then we have;

$\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})$

$\log_e (\frac{1}{5})=-0.1386t$ [ Using $\log_e e^a =a$ ]

$\log_e (0.2)=-0.1386t$

$-1.6094379124341 = -0.1386t$

[using value of $\log_e (0.2) = -1.6094379124341$ ]

then;

$t = \frac{-1.6094379124341}{-0.1386}$

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams

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