The answer is B djiekljfjroeo
Natural numbers: Counting things! You look around your room and see an electronic device, then another, then another! You just counted to 3 using the natural numbers.
Whole numbers! You try to look for electronic devices and realise that they’re all gone. You have zero electronic devices, and you just used whole numbers.
You go online to find where your electronic devices went, and realise they were taken because you’re in debt to the bank so they took some of your stuff. You’re in negative numbers, and now you’ve used integers.
Answer:
14.63% probability that a student scores between 82 and 90
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a student scores between 82 and 90?
This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So
X = 90



has a pvalue of 0.9649
X = 82



has a pvalue of 0.8186
0.9649 - 0.8186 = 0.1463
14.63% probability that a student scores between 82 and 90
This composite figure consists of a right triangle and semicircle
The area of a triangle is: 1/2(bh)
The area of a semicircle is 1/2(pi)(r²)
Plug in the values:
1/2( 12)(8)
=48
1/2(3.14)(4²)
=25.12
25.12+48=73.12
Hope this helped :)
It would be A or B
but not D,C