1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Readme [11.4K]
3 years ago
9

Factoring has nothing to do with finding the least common denominator.

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
6 0

Answer:

  probably FALSE

Step-by-step explanation:

The least common denominator (LCD) of two fractions is the least common multiple (LCM) of their denominators.

One of the ways to find the LCM of numbers is to factor them, then multiply the highest powers of each of the unique factors. Using this method makes your statement FALSE.

__

Another way to find the LCM is to multiply the numbers and divide that product by their greatest common denominator (GCD). Again, finding the GCD can involve factoring, as it is the product of all of the common factors of the numbers.

However, Euclid's algorithm is a method of finding the GCD that does not involve factoring. That is, it is entirely possible to find the LCM of two numbers without doing any factoring, per se. (Though, finding a divisor could be considered factoring.) Using this method makes your statement TRUE.

__

Our guess is that the desired answer is FALSE. Some methods of finding the LCD do involve factoring.

You might be interested in
40pts!! Select the correct answer. <br> Simplify.
stiv31 [10]

Hey!

-------------------------------------------------

Solution:

=\frac{3x^2y^3}{z^3}

Cube the coefficients.

= \frac{27x^2y^3}{z^3}

Multiply the exponents.

= \frac{27x^6y^9}{z^9}

-------------------------------------------------

Answer:

Option D.

-------------------------------------------------

Hope This Helped! Good Luck!

5 0
3 years ago
15 + (5-x)/x=30 solve for x
elixir [45]

Answer:

5/16

Step-by-step explanation:

15+(5-x)/x=30

1) Subtract 15 from both sides:

(5-x)/x=15

2) Multiply both sides by x:

5-x=15x

3) Add x to both sides:

16x=5

4) Divide both sides by 16:

x=5/16

8 0
3 years ago
Help me please I been trying to figure out how to do this problem
Marina86 [1]

sin 30 = x/4

sin 30 = 0.5

0.5 = x/4

x = 2

5 0
1 year ago
1.
mr_godi [17]
Plug the points into the equation.
Ex. y=3x-5
(X,y)
1. (5,10): 10=3(5)-5
15-5=10; point 1 is valid
-1=3(-2)-5
-1=-6-5
-1 does not equal -11
Point 2 is not valid
Same process for letter B
8 0
3 years ago
A phone company charges $0.06 per minute for local calls and $0.15 per minute for international calls. When your bill comes, it
solmaris [256]
Let's assume two variables x and y which represent the local and international calls respectively. 

x + y = 852 = total number of minutes which were consumed by the company (equation 1)
0.06*x+ 0.15 y =69.84 = total price which was charged for the phone calls (Equation 2)
 from equation 1:-
x=852 -y (sub in equation 2)
0.06 (852 - y) + 0.15 y =69.84

51.12 -0.06 y +0.15 y =69.84 (subtracting both sides by 51.12)
0.09 y =18.74
y= 208 minutes = international minutes (sub in 1) 
208+x=852 (By subtracting both sides by 208)
x = 852-208 = 644 minutes = local minutes
6 0
3 years ago
Other questions:
  • A deck of cards with four suits; hearts, diamonds, spades, and clubs. you pick one card, put it back and thennpick another card.
    13·1 answer
  • 2.07 2.67 - 2.67 how do I put them in order from least to greatest
    5·2 answers
  • A cyclist rides her bike at a rate of 21 kilometers per hour. What is this rate in kilometers per minute? How many kilometers
    14·1 answer
  • Graph ƒ(x) = -3x + 7
    6·1 answer
  • Solve this equation for y. <br> 3x - 5y = 12
    12·1 answer
  • You pay $25 for 2 CD's. How much would you pay for 1?​
    8·1 answer
  • Laws Of Indicies<br>Can someone please help me with this?​
    12·2 answers
  • Erika write the following word expression on the board: The quotient of 24 and k. Write an algebraic expression for the word exp
    5·1 answer
  • Does anyone know #13????
    11·1 answer
  • Factors that are unequal across groups and can prevent a researcher from concluding that it was the independent variable that ca
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!