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Readme [11.4K]
4 years ago
9

Factoring has nothing to do with finding the least common denominator.

Mathematics
1 answer:
Nadusha1986 [10]4 years ago
6 0

Answer:

  probably FALSE

Step-by-step explanation:

The least common denominator (LCD) of two fractions is the least common multiple (LCM) of their denominators.

One of the ways to find the LCM of numbers is to factor them, then multiply the highest powers of each of the unique factors. Using this method makes your statement FALSE.

__

Another way to find the LCM is to multiply the numbers and divide that product by their greatest common denominator (GCD). Again, finding the GCD can involve factoring, as it is the product of all of the common factors of the numbers.

However, Euclid's algorithm is a method of finding the GCD that does not involve factoring. That is, it is entirely possible to find the LCM of two numbers without doing any factoring, per se. (Though, finding a divisor could be considered factoring.) Using this method makes your statement TRUE.

__

Our guess is that the desired answer is FALSE. Some methods of finding the LCD do involve factoring.

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3 years ago
In the figure to the right, can you conclude that triangle GHI is congruent to triangle KJI? Justify your reasoning.
inessss [21]

Answer:

No

Step-by-step explanation:

You cannot conclude that ΔGHI is congruent to ΔKJI, because although you can see/interpret that there all the angles are congruent with one another, like with vertical angles (∠GIH and ∠KIJ) and alternate interior angles (∠H and ∠J, ∠G and ∠K), we don't know the side lengths.

All the angles could be congruent, but the sides might be different. For example, ΔGHI might be a bigger triangle than ΔKJI, which could make them similar to one another, but not congruent.

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7 0
3 years ago
In a certain community, 36 percent of the families own a dog and 22 percent of the families that own a dog also own a cat. In ad
zysi [14]

Answer:  a) 0.0792   b) 0.264

Step-by-step explanation:

Let Event D = Families own a dog .

Event C = families own a cat .

Given : Probability that families own a dog : P(D)=0.36

Probability that families own a dog also own a cat : P(C|D)=0.22

Probability that families own a cat : P(C)= 0.30

a) Formula to find conditional probability :

P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\\Rightarrow P(A\cap B)=P(B|A)\times P(A)   (1)

Similarly ,

P(C\cap D)=P(C|D)\times P(D)\\\\=0.22\times0.36=0.0792

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792

b) Again, using (2)

P(D|C)=\dfrac{P(C\cap D)}{P(C)}\\\\=\dfrac{0.0792}{0.30}=0.264

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264

5 0
3 years ago
What is the first step to solve the equation 9h-31=99?
pishuonlain [190]

Add 31 to both sides which will give you

9h = 130

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3 years ago
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