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leva [86]
3 years ago
5

A can of tomatoes has a 4 in. diameter and is 4.5 in. high. What is the area of the paper label that goes around the can

Mathematics
1 answer:
Luden [163]3 years ago
3 0

Answer:

56.5

Step-by-step explanation:

The length of the paper around the can is equal the circumference of the base.

Circumference = πd

Circumference = 3.14 * 4

Circumference = 12.56

And since the height is 4.5 (which is also the width of the paper if you unwrap it), Multiply the circumference by 4.5.

12.56 * 4.5

= 56.52

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A production facility employs 10 workers on the day shift, 8 workers on the swing shift, and 6 workers on the graveyard shift. A
Zigmanuir [339]

Answer:

The probability that all 4 selected workers will be from the day shift is, = 0.0198

The probability that all 4  selected workers will be from the same shift is = 0.0278

The probability that at least two different shifts will be represented among the selected workers is = 0.9722

The probability that at least one of the shifts will be unrepresented in the sample of workers is P(A∪B∪C) = 0.5256

Step-by-step explanation:

Given that:

A production facility employs 10 workers on the day shift, 8 workers on the swing shift, and 6 workers on the graveyard shift. A quality control consultant is to select 4 of these workers for in-depth interviews:

The number of selections result in all 4 workers coming from the day shift is :

(^n _r) = (^{10} _4)

=\dfrac{(10!)}{4!(10-4)!}

= 210

The probability that all 5 selected workers will be from the day shift is,

\begin{array}{c}\\P\left( {{\rm{all \ 4 \  selected   \ workers\  will \  be  \ from  \ the \  day \  shift}}} \right) = \frac{{\left( \begin{array}{l}\\10\\\\4\\\end{array} \right)}}{{\left( \begin{array}{l}\\24\\\\4\\\end{array} \right)}}\\\\ = \frac{{210}}{{10626}}\\\\ = 0.0198\\\end{array}

(b) The probability that all 4 selected workers will be from the same shift is calculated as follows:

P( all 4 selected workers will be) = \dfrac{ (^{10}_4) }{(^{24}_4)}+\dfrac{ (^{8}_4) }{(^{24}_4)} + \dfrac{ (^{6}_4) }{(^{24}_4)}

where;

(^{8}_4) } = \dfrac{8!}{4!(8-4)!} = 70

(^{6}_4) } = \dfrac{6!}{4!(6-4)!} = 15

∴ P( all 4 selected workers is ) =\dfrac{210+70+15}{10626}

The probability that all 4  selected workers will be from the same shift is = 0.0278

(c) What is the probability that at least two different shifts will be represented among the selected workers?

P ( at least two different shifts will be represented among the selected workers)  = 1-\dfrac{ (^{10}_4) }{(^{24}_4)}+\dfrac{ (^{8}_4) }{(^{24}_4)} + \dfrac{ (^{6}_4) }{(^{24}_4)}

=1 - \dfrac{210+70+15}{10626}

= 1 - 0.0278

The probability that at least two different shifts will be represented among the selected workers is = 0.9722

(d)What is the probability that at least one of the shifts will be unrepresented in the sample of workers?

The probability that at least one of the shifts will be unrepresented in the sample of workers is:

P(AUBUC) = \dfrac{(^{6+8}_4)}{(^{24}_4)}+ \dfrac{(^{10+6}_4)}{(^{24}_4)}+ \dfrac{(^{10+8}_4)}{(^{24}_4)}- \dfrac{(^{6}_4)}{(^{24}_4)}-\dfrac{(^{8}_4)}{(^{24}_4)}-\dfrac{(^{10}_4)}{(^{24}_4)}+0

P(AUBUC) = \dfrac{(^{14}_4)}{(^{24}_4)}+ \dfrac{(^{16}_4)}{(^{24}_4)}+ \dfrac{(^{18}_4)}{(^{24}_4)}- \dfrac{(^{6}_4)}{(^{24}_4)}-\dfrac{(^{8}_4)}{(^{24}_4)}-\dfrac{(^{10}_4)}{(^{24}_4)}+0

P(AUBUC) = \dfrac{1001}{10626}+ \dfrac{1820}{10626}+ \dfrac{3060}{10626}-\dfrac{15}{10626}-\dfrac{70}{10626}-\dfrac{210}{10626} +0

The probability that at least one of the shifts will be unrepresented in the sample of workers is P(A∪B∪C) = 0.5256

5 0
3 years ago
How many 1/12 pieces are in 3/3? 3/3 = __/12
adelina 88 [10]

Answer:

Is your teacher trying to confuse us or what?

Step-by-step explanation:

well 3/3 is full so it's just like 12/12, so 12 pieces of 1/12 piece are in 3/3

3 0
2 years ago
Which fraction is greater than the fraction represented by the model?<br> x
aniked [119]

yiiwui. itjirn. riektkkrm. roeoykot.

Step-by-step explanation:

'll

'llhdieo

xodetrd5d5d

n3metnnrnt

tkektmykm uieuieiykir. krjrjunk. irkukkekumk. v. eitkkrn6u. diynkfn. rjynjenynkenukkt 'll

'll

8 0
3 years ago
508,372 in word form
Mars2501 [29]
Five hundred and eight thousand three hundred and seventy two
3 0
4 years ago
What is 832.248 rounded to the nearest tenth? A. 830 B. 832.2 C. 832.25 D. 832.3
OleMash [197]
Hi there.

To start, we have to understand where the ten the place is.

Hint: it's 1 place behind the decimal point.

Now we need to know what numbers behind the tenths place make it round up or down.

If the number behind it is 4 or under, round down.

5 & up, round up.

In this case, 830.248 has 2 numbers behind the decimal, so we have to round those THEN the 2 in the tenths place.

830.25 to 830.3

Your answer is D. 830.3

I know this was lengthy, sorry. Just wanted to explain :p
4 0
3 years ago
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