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UkoKoshka [18]
3 years ago
9

Which of these strategies would eliminate a variable in the system of equations?

Mathematics
2 answers:
KatRina [158]3 years ago
7 0
B. is the correct answer because when adding them together, you would eliminate variable x.
Fofino [41]3 years ago
6 0

Answer:

yes because a is the answer

Step-by-step explanation:

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How many 3/4 cup servings are in 1/2 of a cup of milk? Write your answer in simplest form.
Gekata [30.6K]
The answer to this question would be: 0.375 cups of milk

In this question, you are asked how many cups of milk is 3/4 serving from 1/2 cup of milk. To answer this, you need to multiply the number of serving with the serving size.<span>
</span>If one serving is 1/2 cups of milk, then 3/4 servings would be:
3/4 servings * (0.5 cups / serving)= 3/8 cups of milk = 0.375 cups of milk
5 0
3 years ago
Read 2 more answers
9. Alicia Martin's savings account has a principle of $1,200. It earns 6% interest compounded quartly
zavuch27 [327]

Answer:

9) \$1236.27\,10)\,\$6451.07\, 11)\,\$10,152.87 \,12)\,\$907.95 \,13)\,\$4957.69

Step-by-step explanation:

9) Since Alicia Martin's savings earns 6% quarterly for two quarters then:

A=P(1+\frac{r}{n})^{nt} ⇒ Amount (A), Principle (P), rate (r) in decimal form, number of compoundings (n) a year and t, in year or its fractions.

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=1200(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A=\$1236.27

10) Aubrey Daniel's case:

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=5725(1+\frac{0.04}{4})^{4*3}\Rightarrow A\approx \$6451.07

11) As for Angelo, similarly to Alicia.

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=9855(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$10,152.87

12) Simpson's. For semiannual n=2

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=860(1+\frac{0.055}{2})^{2*1}\Rightarrow A\approx \$907.95

13) Jana Lacey amount:

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=4860(1+\frac{0.04}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$4957.69

6 0
3 years ago
PLEASE HELP ME!!!! I NEED THIS QUICKLY!!
Sergio [31]

Answer:

i79

Step-by-step explanation:

7 0
3 years ago
We want to find the zeros of this polynomial p(x)= ( x^2-1)(x^2-5x+6)
Scrat [10]

Answer:

see explanation

Step-by-step explanation:

To find the zeros let p(x) = 0 , that is

(x² - 1)(x² - 5x + 6) = 0

Factorise each factor

x² - 1 ← is a difference of squares and factors as (x - 1)(x + 1)

x² - 5x + 6 = (x - 2)(x - 3), thus

(x - 1)(x + 1)(x - 2)(x - 3) = 0

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x + 1 = 0 ⇒ x = - 1

x - 2 = 0 ⇒ x = 2

x - 3 = 0 ⇒ x = 3

The zeros are x = ± 1, x = 2, x = 3

4 0
3 years ago
I WILL AWARD BRAINLIEST!! PLEASE HELP!!
Sergeeva-Olga [200]

xy \:  = product \\ xn \times 2y = 2nxy \\

the product will increase by 2n

6 0
3 years ago
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