What is the vertex of y=-2x^2+10x+1 and is it a minimum or maximum
1 answer:
Answer:
Step-by-step explanation:
it is maximum.
when leading coefficient of x² is negative,
It is downward parabola.
or
y=-2x²+10x+1
=-2(x²-5x+(-5/2)²-(-5/2)²)+1
=-2(x-5/2)²+2×25/4+1
=-2(x-5/2)²+25/2+1
=-2(x-5/2)²+27/2
maximum value of y is 27/2 and is attained at x=5/2
vertex is (5/2,27/2)
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Answer:
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Step-by-step explanation:
Wʜᴇʀᴇ ɪs ǫᴜᴇsᴛɪᴏɴ?
Answer:
<em>1, 4.5</em>
Step-by-step explanation:
for midpoint
x₁ = -2, y₁ = 0
x₂ = 4, y₂ = 9
for midpoint
(x₁+x₂)/2 , (y₁+y₂)/2
(-2+4)/2 , (0+9)/2
2/2 , 9/2
1, 4.5
Substitute 22 for x
2(22)-5
44-5
39
Indefinite amount of solutions.
Answer:
A.Y=3/2x-12
Step-by-step explanation:
Option A would be the correct answer.
