Answer:
1)- Variable utilities cost per machine hour = 1.6 per machine hour
2)- Fixed cost = 1740
3)-Total cost on 1220 Machine hour will be
= 3692
Step-by-step explanation:
1) CALCULATE VARIABLE UTILITIES COST PER MACHINE HOUR :
Variable utilities cost per machine hour = Change in cost/high machine hour-low machine hour
=4076-3388/1460-1030
Variable utilities cost per machine hour = 1.6 per machine hour
2) Fixed cost = Total cost-variable cost
= 3388-(1030*1.6)
Fixed cost = 1740
3) Total cost on 1220 Machine hour will be (1220*1.6+1740) = 3692
is a linear polynomial
S<u>tep-by-step explanatio</u>n:
based on the highest power of the variables of a polynomial, it can be classified as linear,polynomial, quadratic polynomial,cubic polynomial etc.
In a linear polynomial, the highest power of the variable is 1. The general form of a linear polynomial is ax+b
In a quadratic polynomial, the highest power of the variables is 2.The general form of quadratic polynomial is 
In a cubic polynomial,the highest power of variable is 3.The general form of cubic polynomial is 
.
Take the given question and simplify it
It is of the form ax+b. Hence it is a linear polynomial.
Answer:
$75.65
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 4.25%/100 = 0.0425 per year,
then, solving our equation
I = 890 × 0.0425 × 2 = 75.65
I = $ 75.65
The simple interest accumulated
on a principal of $ 890.00
at a rate of 4.25% per year
for 2 years is $ 75.65.
Answer:
2! Thank it if it was helpful :D
Step-by-step explanation:
7x-4x=3+3
3x=6
x=2
