We presume your cost function is
c(p) = 124p/((10 +p)(100 -p))
This can be rewritten as
c(p) = (124/11)*(10/(100 -p) -1/(10 +p))
The average value of this function over the interval [50, 55] is given by the integral

This evaluates to
(-124/55)*(ln(65/60)+10ln(45/50)) ≈ 2.19494
The average cost of removal of 50-55% of pollutants is about
$2.19 hundred thousand = $219,000
Answer:
B. 45
Step-by-step explanation:
If im wrong please let me know
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Answer: 112 in sq
Step-by-step explanation: Square: 10 x 10=100 + triangle: 10 - 6 on top = 4
4 x 16 - 10 = 6 on left so... 1/2 x 6 x 4= 12 in sq. So A= 100+12= 112in sq
Its A. Hope this helps, message me for further questions.
Answer:
it’s the third one
Step-by-step explanation:negatives are never higher than numbers without negatives