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3 years ago

Algebra 1 B Unit 7 Lesson 2 Semester B Someone please Help

Mathematics

1 answer:

Dafna1 [17]3 years ago

6 0

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Joel wants to buy a new tablet computer from a store having a 20% off sale on all tablets. The tablet he wants has an original c

earnstyle [38]

Answer:

<u>Joel will have to pay $ 159.60 for the tablet.</u>

Step-by-step explanation:

1. Information given to us to answer the question correctly:

Discount percentage of the tablets = 20%

Original cost of the tablet = $ 190

Sales tax = 5%

2. How much will Joel pay for the tablet? Show your work in your notebook. Remember to use $.

Let's find the discounted price and the sales tax for that price, this way:

Discounted price = Original price - Discount

Discounted price = 190 - (190 * 0.2)

Discounted price = 190 - 38 = 152

Sales tax of the discounted price = 152 * 0.05

Sales tax = 7.60

Joel will have to pay = Discounted price + Sales tax

Joel will have to pay = 152 + 7.60

5 0

3 years ago

What is 2m + 3m² - 4m ? Please show you work. :-)

Alchen [17]

Combine like terms
2m and -4m are like terms while 3m^2 isnt. So, leave 3m^2 as it is and combine the other set. 2m-4m = (-2m). Therefore, your answer should be 3m^2 - 2m

6 0

3 years ago

Choose the answer that best translates

Kryger [21]

Answer:

OPTION B

Step-by-step explanation:

3 and 'a' are multiplied and 5 is subtracted from the result.

OPTION B says 5 less than 3 times a number would fit perfectly.

Other options talk about adding or taking ratios and clearly do not fit the case.

Hence, the right answer is Option B.

7 0

3 years ago

Common minimum of 8, 24, 40?

Brilliant_brown [7]

The common minimum of those three numbers is 120.

3 0

3 years ago

Read 2 more answers

If x+1/x = 5 find the value of x^3 +1/x^3. pls solve

Korolek [52]

Answer:

1) solve x+1/x = 5

$\frac{x + 1}{x} = 5$

$x + 1 = 5x$

$x - 5x = - 1$

$- 4x = - 1$

$x = \frac{ -1}{ - 4}$

$x = \frac{1}{4}$

2) solve x³+1/x³

$x {}^{3} + \frac{1}{x {}^{3} }$

substitute x = 1/4 into the expression

$( \frac{1}{4} ) {}^{3} + \frac{1}{( \frac{1}{4}) {}^{3} }$

$\frac{1}{64} + \frac{1}{ \frac{1}{64} }$

$\frac{1}{64} + \frac{64 \times 1}{1}$

$\frac{1}{64} + 64$

$\frac{4097}{64} \: or \: 64.02$

5 0

3 years ago