Answer:
Correct option is
C
36.25
Modal class =30−40
So we have, l=30,f0=12,f1=32,f2=20 and h=10
⇒ Mode=l+2f1−f0f2f1−f0×h
=30+2×32−12−2032−12×10
=30+6.25
=36.25
∴ Mode =36.25
Answer:
Step-by-step explanation:
<u>For each odd i the term is:</u>
<u>For each even i the term is:</u>
So the sum of the first 100 terms is zero
Answer:
∠P = 39º
∠Q=120º
∠R = 21º
Step-by-step explanation:
m∠P+m∠Q+m∠R=180º (sum of ∠s in a triangle)
2x-3+6x-6+x=180º (substitution)
9x-9=180º (algebra)
9x=189º (algebra)
x=21º (algebra) (this is ∠R)
(2x-3)=39º (algebra) (this is ∠P)
6x-6=120º (algebra) (this is ∠Q)
Answer:
6
Step-by-step explanation:
f(6) = -6 this is the value when the x value is 6
g(5) = -5 this is the value when the x value is 5
4 * f(6) -6*g(5)
4*-6 - 6* -5
-24 + 30
6
Answer:
I believe that its infinitely
(5!*5/4!)
= -