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3 years ago

Rewrite the equation by completing the square. x^{2} +7 x +12 = 0

Mathematics

2 answers:

Mandarinka [93]3 years ago

6 0

Answer:

X=4,3 does that help or are you looking for something else

Step-by-step explanation:

Olegator [25]3 years ago

3 0

Answer:

(x+7/2)^2=1/4

Step-by-step explanation:

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Can somebody please help me I will mark u brilliant

CaHeK987 [17]

Answer: 14

Step-by-step explanation:

Since they said find the mean

You are suppose to add up all the numbers then divide it by how many numbers are there.

3 0

2 years ago

Read 2 more answers

13. Which equation is equivalent to 8x + 4y = -24?

7nadin3 [17]

Answer:

2x + y = - 6

Step-by-step explanation:

Given

8x + 4y = - 24 ( divide each term by 4 )

2x + y = - 6 ← is an equivalent equation

4 0

2 years ago

Find e^cos(2+3i) as a complex number expressed in Cartesian form.

ozzi

Answer:

The complex number $e^{\cos(2+31)} = \exp(\cos(2+3i))$ has Cartesian form

$\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2)$ .

Step-by-step explanation:

First, we need to recall the definition of $\cos z$ when $z$ is a complex number:

$\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}$ .

Then,

$\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}$ . (I)

Now, recall the definition of the complex exponential:

$e^{z}=e^{x+iy} = e^x(\cos y +i\sin y)$ .

So,

$e^{2i-3} = e^{-3}(\cos 2+i\sin 2)$

$e^{-2i+3} = e^{3}(\cos 2-i\sin 2)$ (we use that $\sin(-y)=-\sin y)$ .

Thus,

$e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)$

Now we group conveniently in the above expression:

$e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2$ .

Now, substituting this equality in (I) we get

$\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2$ .

Thus,

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)$

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right]$ .

5 0

2 years ago

Square root of 64 + cube root of 64 is

seropon [69]

Answer:

Step-by-step explanation:

$\sqrt{64}$ + $\sqrt[3]{64}$

= 8 + 4

= 12

8 0

2 years ago

Read 2 more answers

When 12 is added to a number the result is 32 less than 3 times a number.<br> What is this number?

neonofarm [45]

X - the number

$x+12=3x-32 \\
x-3x=-32-12 \\
-2x=-44 \\
x=\frac{-44}{-2} \\
x=22$

The number is 22.

7 0

2 years ago

Read 2 more answers