Answer:
the answer is 5/8
Step-by-step explanation:
Answer:
(3,-4) or x=3 and y= -4
Step-by-step explanation:
I'm going to solve this by substitution
We first need to get a variable by itself in one of the two equations (it doesn't matter which variable and the equation you do the work on doesn't matter either)
I'm going to solve for y in the second equation
-4x-4y=4
add 4y and subtract 4 from both sides to get
-4x-4=4y
Divide by 4 to get
-x-1=y
We can plug this value in for y into the first equation and get
4x+5(-x-1)= -8
Solve for x
4x-5x-5= -8
-x-5= -8
-x= -3
x=3
We can plug this value into one of the first two equations and solve for y
4(3)+5y= -8
12+5y= -8
5y= -20
y= -4
Therefore the solution is (3,-4) or x=3 and y= -4
Answer:
x = 8 units.
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
<em>The areas of the squares adjacent to two sides of a right triangle are 32 unit square and 32 units square. Find the length,x, of the third side of the triangle</em>
My answer:
- Let a is the side length of the 1st square
The area of the 1st square is equal to 32 units square
<=>
<=> a =
units
- Let b is the length of the 2nd square
The area of the 2nd square is equal to 32 units square
<=>
= 32
<=> b =
units
Applying the Pythagoras Theorem, we have:
<=>
<=> 
<=> x = 8 units
Hope it will find you well.
Answer:
9 i think
Step-by-step explanation: