Answer:
3.188
Step-by-step explanation:
Given that :
Sample data: 26.5, 28, 30.2, 29.6, 32.3, 24.7
Sample standard deviation (s) = 2.728
Mean (mu) = 25
Tstatistic formula :
(x - mu) / (s/sqrt(n))
n = sample size = 6 ; s = 2.728 ; mu = 25
Sample mean (x) = (26.5 + 28 + 30.2 + 29.6 + 32.3 + 24.7) / 6
Sample mean (x) = 171.3 / 6 = 28.55
Tstatistic = (28.55 - 25) / (2.728 / sqrt(6))
Tstatistic = 3.55 / 1.1137013
Tstatistic = 3.1875692
= 64^(t^3)*64^(-t/2)
= 64^(t^3)*(64^(-1/2))^t . . . . change the sum of exponents to a product
= 64^(t^3)*(1/√64)^t . . . . . . negative exponent signifies inverse, 1/2 power is sqrt
= 64^(t^3)/8^t . . . . . . . . . . . simplify
= (4^3)^(t^3)/8^t . . . . . . . . . .replace 64 with 4^3
= 4^(3t^3)/8^t . . . . matches the first selection only
Answer:
0.964
Step-by-step explanation:
It's easier to approach this problem if you find the prob. that z is less than -1.8 and then subtract your result from 1.00.
The prob. that z is less than -1.8 can be found using any calculator with probability and statistic functions.
The prob. that z is less than -1.8 = normcdf(-100,-8) = 0.036. Here "cdf" stands for "cumulative probability density function)," -100 is far to the left of z = -1.8, and the result (0.036) is the area under the standard normal probability density curve to the left of z = -1.8.
Finally, subtract this 0.036 from 1.000, obtaining 0.964. This is the probability that z is greater than -1.8.
Answer:
Answer below
Step-by-step explanation:
2.08
2.082
2.8
2.82
√8 (it's 2.8284)
