What is the main denominator of 16/3 and 7/2

Name each ray Calculation Tip: In ray "AB", A is the endpoint of the ray.

Vanyuwa [196]

Answer:

XY→

Step-by-step explanation:

The ray is name from the point to the arrow

XY→

3 0

3 years ago

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Shoes cost $80 they are discounted at 40% off.The tax is 6.75%.What is the final cost of the shoes.

Brilliant_brown [7]

You have to turn the percent into a decimal to do the math.

80 * .40 = 32 (That's the discount.) Now we subtract the orginal price from this.

80 - 32 = 48

Now we need to find the tax value.

48 (our new price) * .0675 = $3.24

Add this back onto the price to get our final price.

3.24 + 48 = $51.24

8 0

3 years ago

Find the a. MEAN and b. STANDARD DEVIATION for the data set. Round to two decimal places.

Dafna11 [192]

Answer:

Explained below.

Step-by-step explanation:

(10)

The data set is:

S = {124, 94, 129, 109, 114}

The mean and standard deviation are:

$\bar x=\frac{1}{n}\sum x=\frac{1}{5}\times [124+94+...+114]=114\\\\s=\sqrt{\frac{1}{n-1}\sum ( x-\bar x)^{2}}$

$=\sqrt{\frac{1}{5-1}\times [(124-114)^{2}+(94-114)^{2}+...+(114-114)^{2}]}\\=\sqrt{\frac{750}{4}}\\=13.6931\\\approx 13.69$

The correct option is B.

(11)

According to the Empirical 95% of the data for a Normal distribution are within 2 standard deviations of the mean.

So, the adult male's height is in the same range as about 95% of the other adult males whose heights were measured.

The correct option is B.

(12)

Let the score be X.

Given:

μ = 100

σ = 26

$X=\mu-2\sigma$

$=100-(2\times 26)\\=100-52\\=48$

The correct option is B.

(13)

Let X be the prices of a certain model of new homes.

Given: $X\sim N(150000, 2300^{2})$

Compute the percentage of buyers who paid between $147,700 and $152,300 as follows:

$P(147700$

$=P(-1$

According to the 68-95-99.7, 68% of the data for a Normal distribution are within 1 standard deviations of the mean.

The correct option is D.

(14)

Compute the percentage of buyers who paid more than $154,800 as follows:

$P(X>154800)=P(\frac{X-\mu}{\sigma}>\frac{154800-150000}{2400})$

$=P(Z>2)\\=0.975\\$

According to the 68-95-99.7, 95% of the data for a Normal distribution are within 2 standard deviations of the mean. Then the percentage of data above 2 standard deviations of the mean will be 97.5% and below 2 standard deviations of the mean will be 2.5%.

The correct option is D.

(15)

The z-score is given as follows:

$z=\frac{x-\mu}{\sigma}$