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Shalnov [3]
3 years ago
15

The graph compares the weights in pounds of 100 dogs and cats that are brought in to a veterinarian's office.

Mathematics
2 answers:
GenaCL600 [577]3 years ago
8 0
In case of dogs the value 10 is the minimum value. So all the values lie above 10. In total there were 100 dogs.
So for dogs, we can say number of dogs above the value of 10 pound are 100.

In case of Cats, 10 lies at the position of median. Median is the central value and 50% values lie above the median value. So number of cats with weight above 10 pound is 50.

Thus, we can conclude that there were 50 more dogs than the cats with weight over 10 pounds. So option C gives the correct answer.
ozzi3 years ago
3 0

Answer:

Just took it!

Step-by-step explanation:

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Either A or D I believe
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Logan spends 26% of his weekly allowance on 2 banana splits. Banana splits cost $3.25 each at Frozen Treats. How much money does
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Write as a fraction.
lesantik [10]

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are inches long, inches wide, and 8 inche
allochka39001 [22]

Answer:

- The number of small boxes that will fill the large box 1 = 64

- The number of small boxes that will fill the large box 2 = 56

Step-by-step explanation:

Complete Question

Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are 4.5 inches long, 4.5 inches wide, and 8 inches tall. To transport the items to an event, you want to know how many of the small boxes will fit in larger boxes. The larger boxes are available in two sizes. Large Box 1 is 24.25 inches long, 18 inches wide, and 24 inches tall. Large Box 2 is 20.5 inches long, 18.5 inches wide, and 24 inches tall. Both the small and large boxes must remain upright.

Solution

To know how many of the small boxes will fit in larger boxes, we need to obtain the volumes of the small box, large box 1 and large box 2.

Volume of a cuboid = L × W × H

For the small box,

Length = L = 4.5 inches

Width = W = 4.5 inches

Height = H = 8 inches

Volume of the small box = 4.5 × 4.5 × 8 = 162 in³

For large box 1,

Length = L = 24.25 inches

Width = W = 18 inches

Height = H = 24 inches

Volume of the large box 1 = 24.25 × 18 × 24 = 10,476 in³

For large box 2

Length = L = 20.5 inches

Width = W = 18.5 inches

Height = H = 24 inches

Volume of the large box 2 = 20.5 × 18.5 × 24 = 9,102 in³

The number of small boxes that'll fill the large box 1 = (10,476/162) = 64.667 = 64 small boxes (rounded down because the fraction cannot be forced into the large box 1.

The number of small boxes that will fill the large box 2 = (9,102/162) = 56.185 = 56 small boxes.

Hope this Helps!!!

7 0
3 years ago
Sin(xy)-x=0 find dy/Dx
MariettaO [177]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2989024

——————————

You have  y  as an implicit function of  x:

sin(xy) – x = 0


Use implicit differentiation. As  y  is a function of  x, then you must apply the chain rule there:

  d                                 d
—— [ sin(xy) – x ]  =  —— (0)
 dx                               dx


  d                           d               d
—— [ sin(xy) ]  –  —— (x)  =  —— (0)
 dx                         dx             dx

  d
—— [ sin(xy) ]  –  1  =  0
 dx

  d
—— [ sin(xy) ]  =  1
 dx
 
                   d
cos(xy)  ·  —— (xy) = 1
                  dx


Now, apply the product rule for that last derivative:

\mathsf{cos(xy)\cdot \left[\dfrac{d}{dx}(x)\cdot y+x\cdot \dfrac{dy}{dx}\right]=1}\\\\\\
\mathsf{cos(xy)\cdot \left[1\cdot y+x\cdot \dfrac{dy}{dx}\right]=1}\\\\\\
\mathsf{y\,cos(xy)+x\,cos(xy)\cdot \dfrac{dy}{dx}=1}


              dy
Isolate  —— :
              dx

                   dy
x cos(xy) · ——  =  1 – y cos(xy)
                   dx


Assuming  x cos(xy) ≠ 0,

 dy          1 – y cos(xy)
——  =  ————————    <———    this is the answer.
 dx            x cos (xy)


I hope this helps. =)

4 0
3 years ago
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