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Leto [7]
4 years ago
14

Passes through ( 4, 7 ) slope =2​

Mathematics
2 answers:
worty [1.4K]4 years ago
7 0

Answer:

y = 2x -1

Step-by-step explanation:

y = mx + b

y = 2x + b

7 = 2(4) + b

7 = 8 + b

-8  -8

-1 = b

ahrayia [7]4 years ago
4 0

Answer:

I'm assuming it's asking for the equation of the line

y = 2x - 1

Step-by-step explanation:

Step 1:  Use the formula y = mx + b to solve

This is slope-intercept form of a line.  We are given the slope of 2 in the question, and a point (x, y), which is (4, 7).  Plug those values into the equation above and solve for b (the only variable we are missing

7 = 2(4) + b

   7 = 8 + b  

   -1 = b

Step 2: Rewrite the formula using the slope and the b value we just calculated

 y = 2x - 1

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Find two numbers with a sum of 14 and a difference of 4:
lara [203]

Answer:

First number --> x

Second number --> y

x + y = 14 --> x = 14 - y

x - y = 4

so

14 - y - y = 4

14 - 2y = 4

2y = 10

y = 5

so

x = 14 -5

x = 9

4 0
3 years ago
Read 2 more answers
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
20 POINTS
olya-2409 [2.1K]

Answer:

x = 5

Step-by-step explanation:

A perpendicular line that passes through the point (5, 0) is a vertical line in which all points have 5 as their x-coordinate.

The slope is undefined since the slope of all vertical lines is undefines.

Answer: x = 5

8 0
3 years ago
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Show that ∆ABC is a right triangle if A(0, 0), B(3, 2), and C(–2, 3). Find the slope m1 of AB and the slope m2 of AC and verify
Mariana [72]

First we'll show this is a right triangle by the Pythagorean Theorem:

A(0,0), B(3,2), C(-2, 3)

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AC^2=(-2)^2+3^2=13

BC^2 = (-3 -3)^2 + (3 -2)^2 = 26

Since AB^2+AC^2=BC^2 we have a right triangle, by the (converse to the) Pythagorean Theorem.  We also see it's isosceles, AB=AC.

\textrm{Slope of AB} = m_1 = \dfrac{2 - 0}{3 - 0} = \dfrac 2 3

\textrm{Slope of AC} = m_2 = \dfrac{3 - 0}{-2 - 0} = -\dfrac 3 2

m_1 m_2 = (\frac 2 3)(-\frac 3 2 ) = -1 \quad\checkmark  

That's the end of the homework but I'll go on a bit.

Another way to show perpendicularity, essentially the same as the other two, is by a zero as the dot product of the sides as vectors, differences between vertices.

Vector AB = B - A = (3,2)

Vector AC = C - A = (-2, 3)

AB · AC = 3(-2) + 2(3) = 0

A zero dot product means

AB ⊥ AC

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
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