Answer:
The Proof is given below.
Step-by-step explanation:
Given:
bisect ∠ EHG.i.e
∴ ∠EHF ≅ ∠ GHF
To Prove:
Proof:
In Δ EHF and Δ GHF
EH ≅ GH ………............{Given}
∠ EHF ≅ ∠ GHF …………..{EF bisect ∠ EHG as given above}
HF ≅ HF ………............{Reflexive Property}
Δ EHF ≅ Δ GHF …................{ By Side-Angle-Side test}
∴ EF ≅ GF........{corresponding parts of congruent triangles (c.p.c.t).}
....... PROVED
The two angles form a right triangle which is 90 degrees.
Add the two to equal 90:
3x-8 + 4x = 90
simplify:
7x-8 = 90
Add 8 to both sides:
7x = 98
Divide both sides by 7:
x = 14
Answer:
False
Step-by-step explanation:
2cos^2(4x) - 1 = cos(8x)
cos(8 *pi/12) = cos(2pi/3) = cos(pi - pi/3) = - cos(pi/3)= 1/2, which is not 0
cos(8x) = 0
==> 8x = 0 or pi
==> x = 0 or pi/8
Is there a picture to go with it?
