$\begin{gathered} probability\text{ of defective p = 10\% = }\frac{10}{100}\text{ = 0.1} \\ \\ probability\text{ of not defective q = 1 - p = 1 - 0.1 = 0.9} \\ \end{gathered}$

Step2

The probability that at least one will have a defect

= 1 - the probability that noon will have a defect

Step 3

Use the binomial distribution

$\begin{gathered} =1\text{ - }^nC_rp^rq^{n-r} \\ n\text{ = 4, r = 0} \\ \\ =1-^4C_0(0.1)^0(0.9)^{4-0} \\ \\ =\text{ 1 - 1}\times1\times0.9\times0.9\times0.9\times0.9 \\ \\ =\text{ 0.344} \end{gathered}$

8 0

2 years ago

Two fathers and two sons went fishing one day. They were there the whole day and only caught 3 fish. One father said, that is en

Drupady [299]

There was a son a dad and his dad. I know this is confusing but there is a son who has a dad and his dad is there as well. So the dad's dad would be the littlest one's grand-dad

5 0

4 years ago

What is the CORRECT answer??

xxTIMURxx [149]

Answer:

y=6x-41

Plug the x and y in to get the constant.

Also, parallel lines have the same slope.

3 0

3 years ago