Question

find three numbers whose sum is 32 if the second is 1 more than the first and the first is 4 less than the third

Answer 1

X+y+z=32
x=z-4
y=x+1
z=x+4
x+x+1+x+4=32
3x+5=32
3x=27
x=9
y=10
z=13

Hope this helps :)