What is the correct answer to this mathematic question X/7=10
2 answers:
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Drawing the tree diagram of the problem, we see that there are 6 branches for drawing from Urn A, and then 4 branches for each of the 6 branches, for drawing from Urn B.
This means that there are 6*4=24 possible outcomes, which could be listed as
{(1, 1), (1, 2), (1, 3), (1, 4), (2, 1)... (6, 3), (6, 4)},
where the first coordinates represent drawing from urn A, and the second coordinates, drawing from urn B.
(4, 2) is one of these 24, so the probability is 1/24
remark, this problem could also have been solved by the multiplication principle of the probabilities of separate events, that is 1/6 (probability of drawing 4 from Urn A) times 1/4 (probability of drawing 2 from B) = 1/24
Answer: 1/24
This means that there are 6*4=24 possible outcomes, which could be listed as
{(1, 1), (1, 2), (1, 3), (1, 4), (2, 1)... (6, 3), (6, 4)},
where the first coordinates represent drawing from urn A, and the second coordinates, drawing from urn B.
(4, 2) is one of these 24, so the probability is 1/24
remark, this problem could also have been solved by the multiplication principle of the probabilities of separate events, that is 1/6 (probability of drawing 4 from Urn A) times 1/4 (probability of drawing 2 from B) = 1/24
Answer: 1/24
Answer:
a) Number of projects in the first year = 90
b) Earnings in the twelfth year = $116500
Total money earned in 12 years = $969000
Step-by-step explanation:
Given that:
Number of projects done in fourth year = 129
Number of projects done in tenth year = 207
There is a fixed increase every year.
a) To find:
Number of projects done in the first year.
This problem is nothing but a case of arithmetic progression.
Let the first term i.e. number of projects done in first year =
Given that:
Formula for term of an Arithmetic Progression is given as:
Where will represent the number of projects increased every year.
and is the year number.
Subtracting (2) from (1):
By equation (1):
<em>Number of projects in the first year = 90</em>
<em></em>
<em>b) </em>
Number of projects in the twelfth year =
Each project pays $500
Earnings in the twelfth year = 233 500 = $116500
Sum of an AP is given as:
It gives us the total number of projects done in 12 years = 1938
Total money earned in 12 years = 500 1938 = $969000