<span>p1=44/88=.50; p2=57/85=.67.
Under the null hypothesis of no difference, we pool the data to estimate the
common p of (44+57)/(88+85)=.584.
The test statistic is (.67-.50)/sqrt[(.584)(1-.584)(1/88 + 1/85)]=2.268 (which is stat sig. at a .095 level).</span>
Answer: 16
Step-by-step explanation:
i did the math trust me
(81m^6)^1/2 = (3^4*1/2) (m^6*1/2) = 3²m³
Answer:
18 roses
Step-by-step explanation:
In the given stem-leaf chart, 18 is the smallest number having 1 as "stem" and 8 as "leaf".
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