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Hunter-Best [27]
3 years ago
9

Did I do this right? Or am I just really stupid lol

Mathematics
1 answer:
Harrizon [31]3 years ago
8 0

3(x-4) <-15

 distribute left side:

3x-12 < -15

 add 12 to each side:

3x <-3

 x < -3/3 = -1

x<-1

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3 years ago
Find the value of x.
s2008m [1.1K]

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3 years ago
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4 0
3 years ago
If <img src="https://tex.z-dn.net/?f=f%28x%29%3D3%5Ex" id="TexFormula1" title="f(x)=3^x" alt="f(x)=3^x" align="absmiddle" class=
SOVA2 [1]

$f(x)+f(x+1) \stackrel{1}{=} 3^x+3^{x+1} \stackrel{2}{=} 3^x+3^x\cdot3^1\stackrel{3}{=}3^x+3\cdot3^x\stackrel{4}{=}4\cdot3^x\stackrel{5}{=}4\cdot f(x)

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8 0
3 years ago
Given ΔRST congruent to ΔNPQ, m∠R = -7x + 9, m∠N = -10x, find m∠R and m∠N. <br><br> PLEASE HELP
zepelin [54]
Answer: m∠R=30° m∠N=30°

If ΔRST is congruent to ΔNPQ, then we can infer that m∠R is congruent to m∠N

m∠R=-7x+9

m∠N=-10x

If both angles are congruent, we can solve for x...

-7x+9=-10x
add 7x to both sides
9=-3x
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Now that we know the value of x, we can solve for the measure of the angles.


m∠R=-7x+9
m∠R=-7(-3)+9
m∠R=21+9
m∠R=30°

m∠N=-10x
m∠N=-10(-3)
m∠N=30°

6 0
3 years ago
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