Answer:
At a certain pizza parlor,36 % of the customers order a pizza containing onions,35 % of the customers order a pizza containing sausage, and 66% order a pizza containing onions or sausage (or both). Find the probability that a customer chosen at random will order a pizza containing both onions and sausage.
Step-by-step explanation:
Hello!
You have the following possible pizza orders:
Onion ⇒ P(on)= 0.36
Sausage ⇒ P(sa)= 0.35
Onions and Sausages ⇒ P(on∪sa)= 0.66
The events "onion" and "sausage" are not mutually exclusive, since you can order a pizza with both toppings.
If two events are not mutually exclusive, you know that:
P(A∪B)= P(A)+P(B)-P(A∩B)
Using the given information you can use that property to calculate the probability of a customer ordering a pizza with onions and sausage:
P(on∪sa)= P(on)+P(sa)-P(on∩sa)
P(on∪sa)+P(on∩sa)= P(on)+P(sa)
P(on∩sa)= P(on)+P(sa)-P(on∪sa)
P(on∩sa)= 0.36+0.35-0.66= 0.05
I hope it helps!
Answer:y=9.5x-0.5
Step-by-step explanation:
Ok, so you need to use the equation y2-y1/x2-x1 to find the slope. So (18.5-4.25)/(2-0.5) so 14.25/1.5 , calculate that and you get 9.5 which is your slope, apply that to the slope formula which is y=mx+b where (m) is slope and (b) is y intercept and you get y=9.5x-0.5
Answer:
m = 
Step-by-step explanation:
Two point slope formula = 
Answer:
4/9
Step-by-step explanation:
8/2=4
18/2= 9
