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Karo-lina-s [1.5K]
3 years ago
5

For questions 1-2 identify the zeros of the function

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
8 0

Answer:

Step-by-step explanation:

The zeros of a function are where it crosses the x axis, so just find the coordinates for the x intercepts.

1.

(2,0) and (-1,0)

2.

(3,0) and (-3,0)

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How can we use ratios and proportional relationships to help us in our daily lives?
ehidna [41]

Answer:

In cooking (recipes).

Step-by-step explanation:

If the serving size for a recipe is not adequate for the number of people you are serving, you will have to convert the amounts(measurements) of the ingredients to suit your needs. You will do this by first creating a ratio defining the relationship between the serving size of the given recipe to the number of people needed to be served. For example, if a recipe serves 4 people, and you need to serve 8, your ratio would simplify to 1/2. This means you must proportionally relate this ratio to the individual amounts of each ingredient.

6 0
3 years ago
What is – 3(8y)? in mathematics form
Katen [24]

Answer:

-24y

Step-by-step explanation:

Use the distributive law

- 3 \times 8y =  - 24y

3 0
3 years ago
Can someone plss answer the Circled question for the dot plot :)))))
frutty [35]
4 has the most. Sorry if it’s wrong, good day to you
8 0
3 years ago
Read 2 more answers
Which expression has a positive value?
Black_prince [1.1K]

Answer:

3 (negative 64 divided by 8) + 25 = 1

Step-by-step explanation:

Negative 4 + (negative 5) (negative 6) divided by (negative 3) = -4 + (-5)(-6)/(-3) = -4 + 30/-3 = -4 - 10 = -14

8 Left-bracket 10 divided by (2) (negative 2) Right-bracket = 8(10/((2)(-2)) = -20

3 (negative 64 divided by 8) + 25 = 3(-64/8) + 25 = 3(-8) + 25 = -24 + 25 = 1

Negative 2 (negative 5) (negative 3) divided by 10 = (-2)(-5)(-3)/10 = -3

The only positive value here is 1, which is a result of 3 (negative 64 divided by 8) + 25

6 0
3 years ago
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H(x)= (x^2 -36)/x +6 explain why the following function is not continuous at x=-6
sergeinik [125]

You can solve this problem through factoring.

First, you have the equation,

h(x) = \frac{x^2-36}{x-6}

Then, you can factor the numerator.

h(x) = \frac{(x+6)(x-6)}{x-6}

You can cancel out the x-6 in both the numerator and the denominator because they would equal to just 1.

You are left with h(x) = x+6

The function is removable noncontinuous at x=6 because if you plug in 6 in x-6, your denominator would be undefined.

8 0
3 years ago
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