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2 years ago

WILL GIVE BRAINLEST

Mathematics

1 answer:

Misha Larkins [42]2 years ago

3 0

Answer:

1/3 chance that you will choose a pizza Witt a thick crust and have topping of either pepperoni or sausage

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I need help please the question is in the picture.

Basile [38]

Answer:

5x+12=42

x=6

Step-by-step explanation:

8+x+x+2+3x+2=42

5x+12=42

5x=42-12

5x=30

x=6

7 0

2 years ago

Find the value of x and the measure of the angle labeled 3x

mafiozo [28]

Answer:

Step-by-step explanation:

45+27=72 and the overall angle is 72

5 0

3 years ago

Read 2 more answers

If C = 18π inches, what is the area?<br><br> I need the answer asap

IRISSAK [1]

I believe it is 56.55 inches I could be wrong but I tried my best

3 0

2 years ago

Read 2 more answers

G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =

Svetach [21]

Presumably you should be doing this using calculus methods, namely computing the surface integral along $\mathbf r(u,v)$ .

But since $\mathbf r(u,v)$ describes a sphere, we can simply recall that the surface area of a sphere of radius $a$ is $4\pi a^2$ .

In calculus terms, we would first find an expression for the surface element, which is given by

$\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k$
$\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j$
$\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k$
$\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u$

So the area of the surface is

$\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u$
$=-2\pi a^2(\cos\pi-\cos 0)$
$=-2\pi a^2(-1-1)$
$=4\pi a^2$

as expected.

6 0

2 years ago

Which statement is true? A.27/19<11/30 B.17/31>19/14 C.16/26>30/31 D.35/30<22/12

Mrac [35]

A. $\frac{27}{19}$

To find greater than or smaller than relation, we multiply the terms like (numerator of L.H.S with denominator of R.H.S and put the value on the left side. Then multiply the denominator of L.H.S with numerator of R.H.S and put the value on right side. Now compare the digits.)

So, solving A, we get 810<209 ... This is false

B. $\frac{17}{31}>\frac{19}{14}$

= 238>589 ..... This is false

C. $\frac{16}{26}>\frac{30}{31}$

= 496>780 .... This is false

D. $\frac{35}{30}$

= 420<660 ..... This is true

Hence, option D is true.

6 0

3 years ago