Answer:
<h2>The area of the base is 144 square inches.</h2><h2>The area of each triangular face is 66 square inches.</h2><h2>Grabiel needs 408 square inches of paint.</h2>
Step-by-step explanation:
The complete problem is attached.
Notice that the figure is a square pyramid, where its base dimensions are 12 inches by 12 inches, which represents an area of
The slant height of the pyramid is 11 inches, which allow us to find the area of each triangle face
But there are four triangle faces, so 
.
Therefore, the area of each triangular face is 66 square inches.
So, the total surface area would be the sum
Therefore, Gabriel needs 408 square inches to paint the whole model.
Answer:
The area is 11317.51
Step-by-step explanation:
The sum of 2 sides must be less than the third side (largest side) for a triangle to be formed.
b+c<a
133+174 < 240
A triangle can be formed
To use Herons formula for the area
We find S = 1/2( a+b+c)
= 1/2(240+133+174)
= 1/2 (547)
= 273.5
Area = sqrt( S (S-a) (S-b)(S-c))
sqrt((273.5 ) (273.5 -240) (273.5-133) (273.5-174))
sqrt((273.5)(33.5) (140.5) (99.5))
sqrt(128085964.4)
11317.50699
The area is 11317.51
Answer:
no
Step-by-step explanation:
fifty eight hundreths= 5,800
5.8<5,800
Answer:
There are a total of 
functions.
Step-by-step explanation:
In order to define an injective monotone function from [3] to [6] we need to select 3 different values fromm {1,2,3,4,5,6} and assign the smallest one of them to 1, asign the intermediate value to 2 and the largest value to 3. That way the function is monotone and it satisfies what the problem asks.
The total way of selecting injective monotone functions is, therefore, the total amount of ways to pick 3 elements from a set of 6. That number is the combinatorial number of 6 with 3, in other words
Answer:
Step-by-step explanation:
Use the "vertical line test." Draw a vertical line through each graph. If the line intersects the graph in more than one place, the graph does NOT represent a function. Only the graph in the upper, right-hand corner represents a function, as a vertical line intersects this graph in only one place.
