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finlep [7]
3 years ago
12

What number should be added to both sides of the equation to complete the square? x2 + 3x = 6

Mathematics
2 answers:
Bond [772]3 years ago
4 0

Answer: It’s B

Step-by-step explanation: I got it right on the test

sladkih [1.3K]3 years ago
3 0
The answer is B because you are suppose to square and divide once you subtract 6 on both sides.
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The sum of the digits of a two-digit number is 10. When the digits are reversed, the new number is 18 less than the original num
eimsori [14]
<h3>Answer:</h3>

64

<h3>Explanation:</h3>

6+4= 10

Then reverse the digits of 64, and you have 46

64-46= 18

3 0
3 years ago
A password is 4 characters long and must consist of 3 letters and one number. if letters cannot be repeated and the password mus
sdas [7]

The possibility of selecting a 4 characters long password consisting of 3 letters and one number if letters cannot be repeated and the password must end with a number is 156000

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more number and variables.

The possibility of selecting the password = 26 * 25 * 24 * 10 = 156000

The possibility of selecting a 4 characters long password consisting of 3 letters and one number if letters cannot be repeated and the password must end with a number is 156000

Find out more on equation at: brainly.com/question/2972832

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7 0
2 years ago
I don’t understand this help
grigory [225]

Answer:

(1,1)(3,-2)

Step-by-step explanation:

a hope this answer helping you

4 0
2 years ago
Read 2 more answers
DETERMINE WHETHER THE EXPRESSIONS BELOW ARE CORRECT OR NOT AND DO THE CORRECTION
Assoli18 [71]

Answer:

First ans is true but second one is not the cotrect

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3 years ago
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For the polynomial function ƒ(x) = x4 −25x2, find the zeros. Then determine the multiplicity at each zero and state whether the
AfilCa [17]

<u>ANSWER</u>

The zeros are x=-5,x=0,x=5


EXPLANATION

Given;

f(x)=x^4-25x^2.


We can rewrite the function as


f(x)=x^2(x^2-25)


\Rightarrow f(x)=x^2(x^2-5^2)


\Rightarrow f(x)=x^2(x-5)(x+5)



The zeros are found by equating the function to zero.


\Rightarrow x^2(x-5)(x+5)=0


\Rightarrow (x-5)=0

The multiplicity is 1, since it is odd the graph crosses at this intercept. which is x=5


Or

\Rightarrow (x+5)=0


The multiplicity is 1, since it is odd the graph crosses at this intercept. which is x=-5


Or


\Rightarrow x^2=0


This last root has a multiplicity of 2.

That is

x=0 repeats two times.


Since the multiplicity is even, the graph touches the x-axis at the point x=0.



See graph.









5 0
3 years ago
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