54/45 · 60/48 ÷ 310/30=

Mathematics

2 answers:

kozerog [31]3 years ago

8 0

54/45 * 60/48 = 1.5

1.5 / 310/30 = 0.00016129032 a.k.a

Hope it helps! :D

love history [14]3 years ago

7 0

Hello
Here is the answer

=9/62
Hope i helped

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saul85 [17]

Here you go!! Hope it helps !!

5 0

3 years ago

What is the length of the altitude of the equilateral triangle below

ale4655 [162]

Using Sine.

Sine = Opposite / Hypotenuse

sin 60° = a / (6√3) But sin60° = √3/2

√3/2 = a/(6√3)

Cross multiply

2*a = 6√3 * √3

2a = 6 * √(3*3)

2a = 6*3

a = 6*3/2

a = 3*3 = 9

Option E.

Hope this helps.

4 0

3 years ago

Suppose a random sample of 50 college students are asked to measure the length of their right foot in centimeters. A 95% confide

hichkok12 [17]

Answer:

A 99% confidence interval will be wider than a 95% confidence interval

Step-by-step explanation:

From the question we are told that

The 95% confidence interval for for the mean foot length for students at the college is found to be 21.709 to 25.091 cm

Generally the width of a confidence interval is dependent on the margin of error.

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

From the above equation we see that

$E \ \ \alpha \ \ Z_{\frac{\alpha }{2} }$

Here $Z_{\frac{\alpha }{2} }$ is the critical value of the half of the level of significance and this value increase as the confidence level increase

Now if a 99% confidence level is used , it then means that the value of

$Z_{\frac{\alpha }{2} }$ will increase, this in turn will increase the margin of error and in turn this will increase the width of the confidence interval

Hence a 99% confidence interval will be wider than a 95% confidence interval

5 0

3 years ago

ANSWER PLZ QUICK AND FAST

Sergio [31]

Jack had b boxes. Then he got 4 more. That is equal to:

$b+4$