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nirvana33 [79]
3 years ago
8

Describe the set of all points p(x,y) in a coordinate plane that satisfy the given condition

Mathematics
1 answer:
IrinaK [193]3 years ago
6 0
Part A:

The line x = -2 is a vertical line passing through point (-2, 0) on the x axis.

The set of points satisfying x = -2 are all the points on the coordinate plane which lies on the vertical line crossing point -2 on the x-axis.



Part B:

The line y = 5 is a horizontal line passing through point (0, 5) on the y axis.

The set of points satisfying y = 5 are all the points on the coordinate plane which lies on the horizontal line crossing point 5 on the y-axis.



Part C:

The line x = 0 is the y axis.

The set of points satisfying x ≥ 0 are all the points on the coordinate plane to the right of the y-axis.



Part D:

The set of points satisfying xy > 0 are all the points on the coordinate plane which lies on the 1st quadrant and all the points on the coordinate plane which lies on the 3rd quadrant.



Part E:

The line y = 0 is the x axis.

The set of points satisfying y < 0 are all the points on the coordinate plane that are below the x-axis.



Part F:

The line x = 0 is the y axis.

The set of points satisfying x = 0 are all the points on the coordinate plane that lie on the y-axis.



Part G:

The line y = -2 is a horizontal line passing through point (0, -2) on the x axis.

The set of points satisfying y = -2 are all the points on the coordinate plane which lies on the horizontal line crossing point -2 on the y-axis.



Part H:

The line x = 4 is a vertical line passing through point (4, 0) on the x axis.

The set of points satisfying x = 4 are all the points on the coordinate plane which lies on the vertical line crossing point 4 on the x-axis.



Part I:

The set of points satisfying x / y < 0 are all the points on the coordinate plane which lies on the 2nd quadrant and all the points on the coordinate plane which lies on the 4th quadrant.



Part J:

The line xy = 0 are the x-axis and the y-axis.

Therefore, the set of points satisfying xy = 0 are all the points on the coordinate plane which lies on the x-axis and all the points on the coordinate plane which lies on the y-axis.



Part K:

The line y = 1 is a horizontal line passing through point (0, 1) on the y axis.

The set of points satisfying y > 1 are all the points on the coordinate plane which lies above the horizontal line crossing point 1 on the y-axis.



Part L:

The line y = 0 is the x axis.

The set of points satisfying y = 0 are all the points on the coordinate plane that lie on the x-axis.
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mylen [45]

Answer:

D is the correct option.

Step-by-step explanation:

In the given table, the first column is for "hours of training" and the second column is for "Monthly pay".

Now, we have to state the meaning of the term h(40)=1820.  

In coordinate system we can write this as (40,1820).

Since, the first column represents "hours of training" and second column is for "Monthly pay". Hence, we can say that for 40 hours of training the monthly payment is $1820.

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Find the equation of a line parallel to −5x+y=2 that contains the point (5,−2). Write the equation in slope-intercept form.
mario62 [17]

Answer:

L2: y-0 = 5/2(x-5)

y = 5/2x-25/2

Step-by-step explanation:

Parallel lines have same slopes.

Line 1,   L1:  5x-2y=20   is in standard form Ax+By=C therefore slope m1= -A/B = -5/-2 = 5/2 or you can solve it for y so you will have the equation in slope-intercept form.

5x-2y = 20

-2y = -5x+20

y = (-5/-2)x+20/(-2)

y = (5/2)x-10 hence m1=5/2 and y-intercept is -10

Line 2 , L2:   y-y1 = m (x-x1),  m=m2=m1=5/2

Point p(5,0) or p(x1,y1) therefore x1=5 , y1=0 and m=5/2

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y = 5/2x-25/2

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2 years ago
Wilfred is feeding his goats. He gives 56% of the bag of feed to the goats in field A and the rest to the goats in field B. If t
krok68 [10]

Answer:

Feeds = 11.76kg

Step-by-step explanation:

Given

Field\ A= 56\%

Field\ B= The\ rest

Bag = 21kg\ feed

Required

Determine how much goats in field A, get.

To do this, we simply multiply the percentage feed received by goats in field A by the actual bags of feeds

i.e.

Feeds = 56\% * 21kg

Convert percentage to decimal

Feeds = 0.56 * 21kg

Feeds = 11.76kg

<em>Hence, goats in field A get 11.76kg of feeds</em>

6 0
2 years ago
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