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nirvana33 [79]
3 years ago
8

Describe the set of all points p(x,y) in a coordinate plane that satisfy the given condition

Mathematics
1 answer:
IrinaK [193]3 years ago
6 0
Part A:

The line x = -2 is a vertical line passing through point (-2, 0) on the x axis.

The set of points satisfying x = -2 are all the points on the coordinate plane which lies on the vertical line crossing point -2 on the x-axis.



Part B:

The line y = 5 is a horizontal line passing through point (0, 5) on the y axis.

The set of points satisfying y = 5 are all the points on the coordinate plane which lies on the horizontal line crossing point 5 on the y-axis.



Part C:

The line x = 0 is the y axis.

The set of points satisfying x ≥ 0 are all the points on the coordinate plane to the right of the y-axis.



Part D:

The set of points satisfying xy > 0 are all the points on the coordinate plane which lies on the 1st quadrant and all the points on the coordinate plane which lies on the 3rd quadrant.



Part E:

The line y = 0 is the x axis.

The set of points satisfying y < 0 are all the points on the coordinate plane that are below the x-axis.



Part F:

The line x = 0 is the y axis.

The set of points satisfying x = 0 are all the points on the coordinate plane that lie on the y-axis.



Part G:

The line y = -2 is a horizontal line passing through point (0, -2) on the x axis.

The set of points satisfying y = -2 are all the points on the coordinate plane which lies on the horizontal line crossing point -2 on the y-axis.



Part H:

The line x = 4 is a vertical line passing through point (4, 0) on the x axis.

The set of points satisfying x = 4 are all the points on the coordinate plane which lies on the vertical line crossing point 4 on the x-axis.



Part I:

The set of points satisfying x / y < 0 are all the points on the coordinate plane which lies on the 2nd quadrant and all the points on the coordinate plane which lies on the 4th quadrant.



Part J:

The line xy = 0 are the x-axis and the y-axis.

Therefore, the set of points satisfying xy = 0 are all the points on the coordinate plane which lies on the x-axis and all the points on the coordinate plane which lies on the y-axis.



Part K:

The line y = 1 is a horizontal line passing through point (0, 1) on the y axis.

The set of points satisfying y > 1 are all the points on the coordinate plane which lies above the horizontal line crossing point 1 on the y-axis.



Part L:

The line y = 0 is the x axis.

The set of points satisfying y = 0 are all the points on the coordinate plane that lie on the x-axis.
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alex41 [277]
X = [-(-8) +/- sqrt((-8)^2 -4*41)] / 2  

x =  ( 8 + sqrt (-100) / 2  and  (8 - sqrt(-100) / 2

 4 +or- 5i
4 0
3 years ago
What is 48% 0f 60,000000
Tanzania [10]
That'd be : 28.8 . I hope this helps. This is it step by step. 

60/x=100/48
<span>(60/x)*x=(100/48)*x       </span>
<span>60=2.08333333333*x      
</span>(2.08333333333) to get x
<span>60/2.08333333333=x </span>
<span>28.8=x </span>
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5 0
3 years ago
Solve for x please and thank you​
Anarel [89]

Answer:

2x -5(x-3) = -4 +5x -29

2x-5x+15 = -4 +5x -29

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6 0
3 years ago
How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0
3 years ago
HELPPPPPPPP PLS!!!!!!!
VikaD [51]

Answer:

(15x + 120) ft³

Or

15(x + 8) ft³

Step-by-step explanation:

The prism can be decomposed into a rectangular prism and a triangular prism

The volume of the prism = volume of the rectangular prism + volume of the triangular prism

✔️Volume of rectangular prism = L*W*H

L = 5 ft

W = 4 ft

H = 6 ft

Volume = 5*4*6 = 120 ft³

✔️Volume of triangular prism = ½*b*h*l

b = x ft

h = 6 ft

l = 5 ft

Volume = ½*x*6*5 = 15x ft³

✔️Volume of the prism = (15x + 120) ft³

6 0
3 years ago
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