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3 years ago

A recipe calls for 8 cups of brown sugar. if i am making 3/4 of the recipe, how much brown sugar should i use?

Mathematics

2 answers:

konstantin123 [22]3 years ago

7 0

Answer:

Step-by-step explanation:

8 dived by 4 equals two

Two times 3 equals six

Use 6 cups of brown sugar for 3/4 of the recipe

sergejj [24]3 years ago

7 0

Answer:

6 cups

Step-by-step explanation:

just dont put all the sugar in there

and that would make no sense<em>n </em>

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A pentagon is formed by connecting the tips of a starfish's leds, as shown below

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Answer:

The area is 161

Step-by-step explanation:

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2 years ago

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2 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

kramer

Step-by-step explanation:

the sum of a number and 2 is no less than the product of 9 and the same number

3 0

2 years ago

The table and the graph each show a different relationship between the same two variables, x and y:

SCORPION-xisa [38]

When x=2 y = 110 which means when when x=1 y = 55
the graph would be 11*55 or 605
The table would be 280/4= 70 70*11=770
Which means the difference is 770-605=165

165 is ur answer

7 0

3 years ago