Simplify x2y5 ____ x6y3
1 answer:
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Answer:
The 99% confidence interval would be given by (0.054;0.154) . So we are confident at 99% that the true proportion of people that they did work at home at least once per week is between 0.054 and 0.154
Step-by-step explanation:
For this case we can estimate the population proportion of people that they did work at home at least once per week with this formula:
We need to find the critical value using the normal standard distribution the z distribution. Since our condifence interval is at 99%, our significance level would be given by and
. And the critical value would be given by:
The confidence interval for the mean is given by the following formula:
If we replace the values obtained we got:
The 99% confidence interval would be given by (0.054;0.154) . So we are confident at 99% that the true proportion of people that they did work at home at least once per week is between 0.054 and 0.154