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nevsk [136]
4 years ago
7

Find the integer that makes this subtraction statement true -3 - ? = -5

Mathematics
1 answer:
Elenna [48]4 years ago
7 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{2}}}}}

Step-by-step explanation:

Let the missing integer be x

Solve for x

\sf{ - 3 - x =  - 5}

Move 3 to right hand side and change it's sign

\dashrightarrow{ \sf{ - x =  - 5 + 3}}

The negative and positive integers are always subtracted but posses the sign of the bigger integer

\dashrightarrow{ \sf{ - x =  - 2}}

Change the signs of both sides

\dashrightarrow{ \boxed{ \sf{x = 2}}}

Hope I helped!

Best regards! :D

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Mars2501 [29]
A=1 b=1 c=- 4 correct answer
4 0
3 years ago
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A plane can travel 5000 kilometers<br> in 6 hours. How far can it travel in<br> 1.5 hours?
kompoz [17]

Answer:

1250 Kilometers.

Step-by-step explanation:

Start by finding the proper ratio of 5000:6. Now divide 6/1.5 to see what we need to divide 5000 by. 6/1.5 is 4. So divide 5000 by 4. This gives you an answer of 1250 kilometers.

3 0
3 years ago
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CONSTRUCTION The area of Liberty Township’s square playground is represented by the trinomial x^2 - 10x + 25. Write an expressio
Phoenix [80]

Answer:

X=5 and X=5

Step-by-step explanation:

X²-10x+25=0

X²-5x-5x+25=0

X(x-5)-5(x-5)=0

(X-5) (x-5)=0

X-5=0. x-5=0

X=5. x=5

4 0
3 years ago
A car travels at 4,400 feet per minute. The radius of each tire on the car is 1 foot . How many revolutions does one of these ti
jeyben [28]
700 rotations
If the radius is 1 foot, the diameter is 2 feet (twice the radius). The circumference of a circle is pi times the radius. Using 22/7 as pi, the circumference of each tire is (22/7)*2 feet. That is the same as 44/7 feet.
If the car is going 4400 feet per minute, the tires will "rotate 4400 feet from the circumference" - if you know what I mean. The tire completes one rotation every 44/7 feet. So, in 4400 feet it will complete (4400)/(44/7) feet. That is equal to 4400*7/44. Put that in a calculator and you get: 700.
**
7 0
3 years ago
For what values of k the relation R:{(k2 , 5), (3k, 6)} is not a function?
n200080 [17]
<h3>Answer:  k = 0 or k = 3</h3>

Explanation:

If you have repeated x values, then you wont have a function. For example, the points (1,5) and (1,6) mean we don't have a function since the input x = 1 leads to multiple outputs y = 5 and y = 6 simultaneously. For a function to be possible, we must have any input lead to exactly one output only.

What we do is set the x coordinates (k^2 and 3k) equal to each other and solve for k

k^2 = 3k

k^2-3k = 0

k(k-3) = 0 .... factoring

k = 0 or k-3 = 0 .... zero product property

k = 0 or k = 3

If k = 0, then (k^2,5) becomes (0,5). Also, (3k,6) becomes (0,6). The two points (0,5) and (0,6) mean the graph fails the vertical line test.

Similarly, if k = 3, then (k^2,5) becomes (9,5) and (3k,6) = (9,6). Another vertical line test failure happens here to show we don't have a function.

7 0
4 years ago
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