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seropon [69]
3 years ago
13

enrique says that to round a decimal to the nearest integer, you can just ignore the decimal part. Is enrique correct? Explain

Mathematics
1 answer:
Delvig [45]3 years ago
4 0

Answer:

No

Step-by-step explanation:

No, the decimal part is important.

For example, 1.4≈1, but 1.5≈2

Therefore, Enrique is wrong.

You might be interested in
Evaluate 6j+ 23+k/l−3, when j=3, k=7, and l=33. Enter your answer in the box.
LekaFEV [45]
<span>83.212121 or fraction form is </span>83 7/33​<span> </span>
7 0
3 years ago
Mitchell took out a loan for $1100 at a 19.2% APR, compounded monthly, to
goldenfox [79]

Answer:

C. 18

Step-by-step explanation:

We can find the numbers of payments using following formula

PV = PMT(1- (1+r)^-n)/r

PVr / PMT = 1 - (1+r)^-n

Where

PV = present value = $1,100

PMT = monthly payments = $71.50

r = interest rate = 19.2% / 12 = 1.6%

n = numbers of month = ?

Placing values in the formula

(1+r)^-n = 1 - PVr /PMT

1.016^-n = 1-1100 x 0.016/71.50

1.016^-n = 0.753846154

-n x log 1.016 = log 0.753846154

n = - log 0.753846154 /log 1.016

n = 17.8

n = 18 payments

4 0
4 years ago
Johnny paid $19 for a pair of jeans. It was originally $33. What percent discount did he receive?
Ber [7]

Answer:

Approximately 42.42%

Step-by-step explanation:

If you subtract 42.42% from 33 it equals approx 19.

4 0
3 years ago
What is (t)? 0=18000*0.988^t
lutik1710 [3]
0=1. The answer is No Solution.
6 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title="f(x) = \sqrt{x} " alt="f(x) =
Georgia [21]

Answer:    \dfrac{1}{2\sqrt x}

<u>Step-by-step explanation:</u>

\lim_{h \to 0} f(x)=\dfrac{f(x+h)-f(x)}{h}

f(x) = \sqrt x\\

f(x+h) = \sqrt{x+h}

\lim_{h \to 0} f(x)=\dfrac{\sqrt{x+h}-\sqrt x}{h}

                   =\dfrac{\sqrt{x+h}-\sqrt x}{h}\bigg(\dfrac{\sqrt{x+h}+\sqrt x}{\sqrt{x+h}+\sqrt x}\bigg)

                   =\dfrac{(x + h)-(x)}{h(\sqrt{x+h}+\sqrt x)}

                   =\dfrac{h}{h(\sqrt{x+h}+\sqrt x)}

                   =\dfrac{1}{\sqrt{x+h}+\sqrt x}

                  =\dfrac{1}{\sqrt{x+0}+\sqrt x}

                  =\dfrac{1}{2\sqrt x}

4 0
4 years ago
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