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4 years ago

HELP PLEASE EQUATION OF PARABOLA

Mathematics

1 answer:

Masteriza [31]4 years ago

6 0

It has a minimum value at x = 3 and f(x) = 4

Vertex form is

f(x) = a(x - 3)^2 + 4 where a is some constant to be found

From the graph when x = 5 f(x) = 15, so

15 = a * 2^2 + 4

a = 15-4/4 = 11/4

so our equation is f(x) = 11/4(x - 3)^2 + 4

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A line is graphed below. Write an equation in the form y = mx + b that represents this line

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<h3>Explanation</h3>

Slope-Intercept form

$y = mx + b \\ m = slope \\ b = y - intercept$

Calculate the slope with two given coordinate by using rise over run.

$\begin{cases}(x_1,y_1) = ( - 4,0) \\ (x_2,y_2) = ( 0,2) \end{cases}$

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Rewrite the equation in slope-intercept.

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Calculate the y-intercept by substituting any given points in new rewritten equation.

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I will be substituting these coordinate points in the equation.

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Therefore the y-intercept is (0,2).

Rewrite the equation.

$y = \frac{1}{2} x + 2$

<h3>Answer</h3>

 $\large \boxed{y = \frac{1}{2} x + 2}$ 

If you have any questions related to the answer, feel free to ask me via comment.

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3 years ago

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Greeley [361]

It would be D) 121

All you have to do is add 26 to 95.

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