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3 years ago

7x = -63 - 11y 8x = 93 + 11y

Mathematics

1 answer:

Irina18 [472]3 years ago

7 0

Y=mx+b now just re do them

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Step-by-step explanation:

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Find the domain and range of the relation: {(–20, 11), (6, –8), (1, –20), (–13, 13)}

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Answer:

D: {-20, -13, 1, 6}

R: {-20, -8, 11, 13}

Step-by-step explanation:

Given the relation, {(–20, 11), (6, –8), (1, –20), (–13, 13)}, all x-values (inputs) make up the domain of the relation while all y-values make up the range of the relation.

Therefore:

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Range: {-20, -8, 11, 13}

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3 years ago

What is the following product

Genrish500 [490]

For this case we must find the product of the following expression:

$\sqrt [3] {5} * \sqrt {2}$

By definition of properties of powers and roots we have:

$\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}$

We rewrite the expression using the lowest common index of 6, then:

$5 ^ {\frac {1} {3}} * 2 ^ {\frac {1} {2}} =$

We rewrite the terms in an equivalent way:

$5 ^ {\frac {2} {6}} * 2 ^ {\frac {3} {6}} =$

We rewrite the expression using the property mentioned:

$\sqrt [6] {5 ^ 2} * \sqrt [6] {2 ^ 3} =$

We combine using the product rule for radicals:

$\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}$

So:

$\sqrt [6] {5 ^ 2 * 2 ^ 3} =\\\sqrt [6] {25 * 8} =\\\sqrt[6]{200}$

ANswer:

Option b

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