We can first add up the cards so we know how many we have in all:
16 + 16 + 18 = 50 cards
We can do this a little bit easier if we get the "16"-cards in one number total.
16 + 16 = 32

= 32 x 2 =

50 x 2

= 64 : 2 = 32 %
100
We did just divide the % of two types cards on 2, so we get the %-chance of 1 type card.
I am not quite sure, but I think that 32 % is the correct answer.
To find AB(x) and BC(y), you can do(there are multiple ways you can do this):
tan A = 
tan 60° =
or (tan 60°) · 7 = y
tan 60° = 
√3 · 7 = y
7√3 cm = y
sin B = 
sin 30° =
or 
sin 30° =
= 
x = 
x = 14 cm
AB = 14cm
BC = 7√3 cm
What is the question marks for?
The First One Answer is
x•(1+xy+x^2y)
Hey, here's a pic of it ! hope this helps !
p.s., photomath is a good app for algebraic answers with work, you should check it out (:
Answer:
Step-by-step explanation:
Use synthetic division to answer this. If the remainder is zero, then we can safely assume the divisor (x + 7) is a factor of the polynomial f(x)= x^3-3x^2+2x-8.
We use -7 as the divisor in synth. div. This comes from the factor (x + 7):
-7 / 1 3 2 -8
-7 28 -210
-------------------------
1 -4 30 -218
Here, the remainder is -218, not zero, so no, (x+7) is not a factor of f(x)= x^3-3x^2+2x-8.