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4 years ago

What is the coefficient variable of 5c-15

Mathematics

1 answer:

timurjin [86]4 years ago

8 0

The coefficient of this expression is 5, a coefficient is just the number before a variable.

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Solve for the following equation. 7=r^1/2 please help

Andreas93 [3]

7 = r^1/2 is the same as saying 7 = square root of r. So, to get rid of the square root sign on the r, you need to square it, and when you do something to one side of the equation, you have to do the same to the other side. So after squaring both sides, you get 49 = r.

6 0

3 years ago

The original price of an item is 120 but there is a sale for 80

Bad White [126]

Answer:

33.3%

Step-by-step explanation:

It was a sale for 33.3% off.

80=66.6% of 120

the last third, which is 40, equals 33.3% of 120

40 is 1/3 of 120

1/3=33.3%

8 0

3 years ago

Find the x value in the isosceles triangle shown below.

stiks02 [169]

Answer:

X=^49

Step-by-step explanation:

5 0

3 years ago

The height (feet) of an object moving vertically is given by s= (-16t^2)+(208t)+(156), where t is in seconds.

OverLord2011 [107]

Answer:

The object's velocity at t = 7 is -16 ft/s

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

Step-by-step explanation:

From the information given, the equation of motion of the object is

$s(t)= -16t^2+208t+156$

For any equation of motion s(t), the instantaneous velocity at time t is given by

$v(t)=\frac{ds}{dt}$

(a) To find the object's velocity at t = 7, you must:

$v(t)=\frac{d}{dt}(-16t^2+208t+156)\\\\v(t)=-\frac{d}{dt}\left(16t^2\right)+\frac{d}{dt}\left(208t\right)+\frac{d}{dt}\left(156\right)\\\\v(t)=-32t+208+0\\\\v(t)=-32t+208$

Next, we evaluate when t = 7

$v(7)=-32(7)+208=-224+208\\\\v(7)=-16$

The object's velocity at t = 7 is -16 ft/s

(b) <em>To find the maximum of a function we always use the derivative of the function and we set it equal zero to find the</em><em> critical points.</em>

To find the maximum height and when it occurs, we set the velocity function equal to 0 and solve for t.

$-32t+208=0\\\\-32t+208-208=0-208\\\\-32t=-208\\\\\frac{-32t}{-32}=\frac{-208}{-32}\\\\t=\frac{13}{2}$

Next, we substitute this value into the equation of motion to find the maximum height

$s(\frac{13}{2})= -16(\frac{13}{2})^2+208(\frac{13}{2})+156\\\\s(\frac{13}{2})=-676+1352+156)=832$

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

6 0

4 years ago

Select the correct answer. if you roll a single six-sided die, what is the probability of rolling an odd number? a. b. c. d. 3

Mamont248 [21]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

P(odd number)= $\frac{3}{6}$

= $\frac{1}{2}$

5 0

2 years ago