Por favor alguien dígame el nombre de la figura

The price of one share of Starbucks declined five dollars per day for four days in a row. How much did the price of one share ch

myrzilka [38]

Answer:

Each share lost $20 in value over 4 days time

Step-by-step explanation:

$5 loss for 4 days

5 x 4 = 20

$20 loss in 4 days.

5 0

3 years ago

HELPPPPPPPPPPPPPPPPPPPPP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE! asap

Zinaida [17]

Answer:

209.25 ft²

Step-by-step explanation:

2.7cm * 5 = 13.5 ft

3.1cm * 5 = 15.5 ft

Area

a = 13.5 * 15.5

a = 209.25 ft²

3 0

3 years ago

Read 2 more answers

What is two consecutive integers 181

exis [7]

So our integer and the consecutive integer . The smaller integer is 90.

8 0

3 years ago

Read 2 more answers

What’s the standard form of the line that passes through (6, 1) and (5, 4)

Mnenie [13.5K]

Answer:

3x + y = 19

Step-by-step explanation:

Find the Slope:

4 - 1 / 5 - 6 = m

3/-1 = m

-3 = m

Find b: (use one of the points given and plug into y = mx + b)

1 = 6 (-3) + b

1 = -18 + b

19 = b

Plug the m and b you just found into y = mx + b

y = -3x + 19

Change to standard form (Ax + By = C)

3x + y = 19

8 0

3 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago