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Debora [2.8K]
4 years ago
8

If line ℓ is parallel to plane P, how many planes containing line ℓ can be drawn parallel to plane P?

Mathematics
1 answer:
Slav-nsk [51]4 years ago
7 0

Answer:

One

Step-by-step explanation:

Only one plane containing line ℓ can be drawn parallel to plane P

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Figure B is a scaled copy of Figure A.
muminat

Answer:

1/3

Step-by-step explanation:

We are going to a small shape from a big shape, so the scale factor must be less than 1.

3 (which is a side on the blue figure) and 9 (a side on the green figure)

3 and 9 are easy numbers (for me...) so 3:9 is smaller than 1.

3:9 simplified is 1:3 = 1/3

so 1/3 is the scale factor.

Let's make sure it's right....

9 * 1/3 (green figure to blue figure) is = 3.

3.6 * 1/3 = 1.2

you can check it yourself on a calculator if you don't believe me

I hope this helps have a great day!!!!

7 0
4 years ago
Read 2 more answers
I need help with solving isosceles and equilateral triangles
Scilla [17]

Answer:

60º

Step-by-step explanation:

The interior angles of a triangle equals 180º. And 60+60+60=180, that is your answer.

3 0
2 years ago
Help me please and thanks
Stels [109]
ΔMAX
ΔMXA
ΔXAM
ΔXMA
ΔAXM
ΔAMX
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Bolded are your answers. The others are if i missed some of the choices. To have a triangle name, it must all be angles, and no side lengths.


hope this helps
3 0
4 years ago
Read 2 more answers
Find the x-intercept of 2x+2y=2
Nana76 [90]

Answer:

x-intercept: <u>(1,0)</u>

y-intercept: <u>(0,1)</u>

Step-by-step explanation:

Given: Find the x and y intercepts of 2x + 2y = 2

<h2><u>X-intercept</u></h2>

To solve for a x - intercept we have to substitue 0 in for y and solve for x

Lets do it:

2x + 2(0) = 2

2x + 0 = 2

2x = 2

x = 1

Therefore, this means that when y = 0, x = 1 or (1,0)

<h2><u>Y-intercept</u></h2>

To solve for a y - intercept we have to substitue 0 in for x and solve for y

Lets do it:

2(0) + 2y = 2

0 + 2y = 2

2y = 2

y = 1

Therefore, this means that when x = 0, y = 1 or (0,1)

3 0
2 years ago
A ball is thrown from a height of 38 meters with an initial downward velocity of 3 m/s
ANTONII [103]
<h2>Hello!</h2>

The answer is:

The ball will hit the ground after t=2.47s

<h2>Why?</h2>

Since we are given a quadratic function, we can calculate the roots (zeroes) using the quadratic formula.  We must take into consideration that we are talking about time, it means that we should only consider positive values.

So,

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}

We are given the function:

h=-5t^{2}-3t+38

Where,

a=-5\\b=-3\\c=38

Then, substituting it into the quadratic equation, we have:

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}=\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}\\\\\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}=\frac{3+-\sqrt{9+760} }{-10}\\\\\frac{3+-\sqrt{9+760} }{-10}=\frac{3+-\sqrt{769} }{-10}=\frac{3+-27.731}{-10}\\\\t1=\frac{3+27.731}{-10}=-3.073s\\\\t2=\frac{3-27.731}{-10}=2.473s

Since negative time does not exists, the ball will hit the ground after:

t=2.473s=2.47s

Have a nice day!

4 0
3 years ago
Read 2 more answers
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